Why Is Calculating Golf Ball Velocity More Challenging on a Downhill Lie?

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SUMMARY

The discussion focuses on the challenges of calculating golf ball velocity on a downhill lie compared to an uphill lie. It establishes that a golf ball decelerates at 2.0 m/s² going downhill and at 3.0 m/s² going uphill. The problem involves calculating the allowable range of initial velocities for a putt from 7.0 meters away from the cup, ensuring the ball stops within 1.0 meter of the target. The results indicate that the downhill putt is more difficult due to the lower deceleration rate, which affects the control over the ball's stopping distance.

PREREQUISITES
  • Understanding of kinematic equations, specifically V² = vo² + 2a(x - xo)
  • Knowledge of acceleration concepts in physics
  • Familiarity with golf putting mechanics
  • Basic problem-solving skills in physics
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  • Calculate initial velocities for uphill and downhill lies using the kinematic equation
  • Explore the effects of different deceleration rates on ball control
  • Research advanced golf putting techniques and their physics
  • Investigate the impact of slope on golf ball dynamics
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Golf enthusiasts, physics students, and sports scientists interested in the mechanics of golf putting and the effects of terrain on ball dynamics.

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Homework Statement

In putting the force with which a golfer strikes ball is planned so that the ball will stop within some small distance of the cup say 1.0 m long or short in case the putt is missed. Acomplishing this from an uphill lie(that is putting downhill) is more difficult than from downhill lie. To see why assume that on a particular green the ball decelerates constantly at 2.0m/s^2 going downhill and constantly going at 3.0 m/s^2 going uphill. Suppose we have an uphill lie 7.0m from the cup. Calculate the allowable range of velocities we may impart to the ball so that it stops in the range 1.0m short to 1.0m long of the cup. Do the same for a downhill lie 7.0m from the cup. What in your results suggests that the downhill putt is more difficult?



Homework Equations

V^2=vo^2+2a(x-xo)



The Attempt at a Solution

I am not sure where to start
 
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welcome to pf!

hijburrus! welcome to pf! :smile:

(try using the X2 and X2 icons just above the Reply box :wink:)

forget all about this "uphill" and "downhill" guff …

just use the given figures of 2.0 and 3.0 m/s2, and find the v0 corresponding to the given distances …

what do you get? :smile:​
 

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