# Calculate the allowable range of initial velocities

Hi all. I'm stuck on a physics problem obviously...So the original problem basically is a golfer is trying to put a ball 1.0m long or short of the cup. From uphill it is more difficult than downhill-explain why. Assume that the ball decelerates constantly at 2.0m/s^2 going downhill, and constantly at 3.0 m/s^2 going uphill. The uphill and downhill lie are both 7.0m from the cup. I'm supposed to calculate the allowable range of initial velocities that can be imparted on the ball so that it stops in the 1.0m long or short range from the cup.

I wrote down my given for this: (hope i got it right)
a(up)=2.0m/s^2
a(down)=-3.0m/s^2
V(init)=?
V(final)=0m/s
x(down)=-7.0m
x(up)=7.0m (should the distance be different since the golfer can hit it anywhere between 6m-8m?)

I tried using the V(init)=sqrt[V(final)-2a(x-x(init)], but i don't think i'm doing it right. Can someone give me some pointers or explain this problem a bit more? Thanks for the help!

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