Why is Electron Affinity Negative for Period 2 & 3 Elements?

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SUMMARY

The discussion centers on the concept of electron affinity (E.A.) for elements in periods 2 and 3 of the periodic table. It is established that the first electron affinity is always negative, indicating an exothermic reaction when a gaseous atom accepts an electron. While E.A. generally decreases down a group due to increased electron shielding, period 3 elements exhibit smaller electron affinities than period 2 elements, with the notable exception of fluorine (F) having a lower E.A. than chlorine (Cl) despite its higher electronegativity. This is attributed to the small atomic size of F, which results in greater electron density and requires more energy to accommodate an additional electron.

PREREQUISITES
  • Understanding of electron affinity and its significance in chemistry.
  • Familiarity with the periodic table, particularly the arrangement of elements in periods and groups.
  • Knowledge of exothermic and endothermic reactions.
  • Basic concepts of atomic structure, including electron shielding and atomic size.
NEXT STEPS
  • Research the concept of electron affinity in detail, focusing on the first and second electron affinities.
  • Study the periodic trends in electronegativity and how they relate to electron affinity.
  • Examine the exceptions to general trends in electron affinity, particularly for halogens.
  • Explore the implications of electron affinity on chemical reactivity and bonding.
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Chemistry students, educators, and professionals interested in understanding periodic trends, electron behavior, and the underlying principles of chemical reactions.

ritwik06
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Why is electron affinity negative?

In my book its written, that on moving down a group, tit decreases. But why is it that period 3 elements have greater E.A. than period 2 elements?
 
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you should precise which E.A.! The first E.A. is the amount of energy released when 1 mol of a gaseous atom accepts 1 mol electrons. the first E.A. is always negative. E.A. is in fact an energy change; when an energy change is -ve, it implies that the reaction is exothermic, i.e energy is liberated...and when energy change is +ve, it implies that the reaction is endothermic, i.e energy is absorbed. right

the attraction between the nucleus and the first electron to be accepted releases energy. the second E.A. and succeeding ones are all endothermic. this is because energy is needed to force the electron into the atom. energy is now required as the second incoming electron is being at the same time attracted by the nucleus and repelled(to a larger extent) by the other electrons of the atom. right

E.A. decreases down a group. this is because, down a group the atoms become shielded by the larger numbers of electrons. (e.g. Li has 3 e-, Na has 11e-, K has 19e-,...) the shielding decreases the attractive force of the nucleus on the incoming electron and furthermore, the incoming electron is being repelled at a greater extent by the larger number of electrons. i.e more energy is required to force that electron into the atom.

period 3 elements have SMALLER electron affinities than period 2 elements for the reasons above. But an exception is F(period 2) and Cl(period 3). This is due to the fact that F has a very small size...

Hope i helped you
 
Kushal said:
period 3 elements have SMALLER electron affinities than period 2 elements for the reasons above. But an exception is F(period 2) and Cl(period 3). This is due to the fact that F has a very small size...

Hope i helped you

how is that an exception?...doesnt F have a greater E.A than Cl?

ritwik06 said:
Why is electron affinity negative?

In my book its written, that on moving down a group, tit decreases. But why is it that period 3 elements have greater E.A. than period 2 elements?

did u switch period and group by accident? The rule of thumb is that the closer something is to Flourine the larger its E.A is...
 
Kushal said:
you should precise which E.A.! The first E.A. is the amount of energy released when 1 mol of a gaseous atom accepts 1 mol electrons. the first E.A. is always negative. E.A. is in fact an energy change; when an energy change is -ve, it implies that the reaction is exothermic, i.e energy is liberated...and when energy change is +ve, it implies that the reaction is endothermic, i.e energy is absorbed. right

the attraction between the nucleus and the first electron to be accepted releases energy. the second E.A. and succeeding ones are all endothermic. this is because energy is needed to force the electron into the atom. energy is now required as the second incoming electron is being at the same time attracted by the nucleus and repelled(to a larger extent) by the other electrons of the atom. right

E.A. decreases down a group. this is because, down a group the atoms become shielded by the larger numbers of electrons. (e.g. Li has 3 e-, Na has 11e-, K has 19e-,...) the shielding decreases the attractive force of the nucleus on the incoming electron and furthermore, the incoming electron is being repelled at a greater extent by the larger number of electrons. i.e more energy is required to force that electron into the atom.

period 3 elements have SMALLER electron affinities than period 2 elements for the reasons above. But an exception is F(period 2) and Cl(period 3). This is due to the fact that F has a very small size...

Hope i helped you


Yes understood it quite well now. But please do tell me that while comparing electron affinities of 2 elements, do we consider the -ve sign?

Thanks a lot for the valuable help.
 
TripleS said:
how is that an exception?...doesnt F have a greater E.A than Cl?


Nope. Though F is more electronegative than Cl, E.A of F is less than Cl. It is because F is comparatively very small atom which give it higher electron density than it's neighbours. If you want to place an electron in it's (F)outermost shell you have to do some extra work (for the extra density of electrons it has). So overall it effects the net realease of energy.
 
the sign is just to distinguish between a reaction being exothermic or endothermic. -ve means exothermic and +ve means endothermic.

for example... first EA of Cl is - 364, Br is -342, I is -295. It just means that, when 1 mol Cl accepts 1 mol e-, 364kJ of energy is liberated. For Br it's 342 kJ and for I it's 295 kJ. The amount of energy liberated decreases from Cl to Br...and therefore e- affinity decreases.

So... the answer is no.
 

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