Pjpic
- 235
- 1
Why should it be obvious that:
e raised to i (pi) = -1
e raised to i (pi) = -1
Last edited:
The discussion revolves around the question of why the equation \( e^{i\pi} = -1 \) is not immediately obvious to individuals encountering it for the first time. Participants explore the implications of Euler's formula and the connections between exponential and trigonometric functions, addressing both conceptual and mathematical perspectives.
Participants generally agree that the relationship becomes clearer with further mathematical understanding, but there is no consensus on whether it is inherently obvious or remains unobvious for new learners.
Some participants note that the initial lack of clarity may stem from the dependence on definitions and prior knowledge of complex functions and their properties. The discussion also touches on the limitations of intuition in mathematics, particularly for those without a strong background in the subject.
This discussion may be of interest to students and educators in mathematics, particularly those exploring complex analysis, exponential functions, and their connections to trigonometry.
Pjpic said:Why should it be obvious that:
e raised to i (pi) = -1
Hmm..why did you edit into my comment something I didn't say in this context, HallsofIvy?HallsofIvy said:It is after you have Euler's formula!
I am so sorry. I meant to edit MINE and accidently clicked on the wrong button!arildno said:Hmm..why did you edit into my comment something I didn't say in this context, HallsofIvy?
Sure,if you define the complex exponential by Euler's formula, then it is "obvious" that the result follows.
However, it still remains unobvious, prior to proving, say, De Moivre's formula, that exponentials should have anything to do with trig functions in their complex forms.
mgb_phys said:It's easier to see in polar form http://en.wikipedia.org/wiki/Image:Euler's_formula.svg
Remember that pi (rad) is 180deg so the arrow moves 180deg anti clockwise and points to -1 on the real axis.
arildno said:Sure,if you define the complex exponential by Euler's formula, then it is "obvious" that the result follows.
However, it still remains unobvious, prior to proving, say, De Moivre's formula, that exponentials should have anything to do with trig functions in their complex forms.
Pjpic said:I wonder if you can explain it in english. Gauss said that it would be obvious to person with a future in math (I don't even have a past in math). But it seem like 2.71 to 3.14 = about 23. How does using the imaginary number make it equal -1?
A) It remains unobvious for every new generation.rbj said:personally, i think that De Moivre's follows from Euler's. the more fundamental formula is Euler's.
anyway, outside of calculus, it is unobvious that exponential functions have any relationship to trig functions. but once you start thinking about derivatives, that the derivative of an exponential is another exponential (with the same "[itex]\alpha[/itex]" inside) and the derivative of a sinusoidal function is another sinusoid (with the same "[itex]\omega[/itex]" inside), that you might start to wonder that there is a connection. then, once you get to Taylor or Maclaurin Series, and you compare the series for sin() and cos() and ex, then it becomes less and less unobivious.
but someone had to have the insight for seeing it first, and Euler, whom some folks think is the "Einstein" of mathematics, was the first to see it. now, it's sort of obvious.