Why is My Polarized Plate Field Calculation Incorrect?

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The discussion revolves around a misunderstanding in calculating the polarized plate field, specifically regarding the relationship between polarization (P), permittivity (ε), and the electric field (E). The user presents their calculation but expresses confusion over its correctness. A key point raised is the potential confusion between the applied electric field and the local field, which can lead to incorrect results. Clarifying these concepts is essential for accurate calculations in electrostatics. Understanding the distinction between applied and local fields is crucial for resolving the issue.
LCSphysicist
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Relevant Equations
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I am a little confused why my answer is wrong... Briefly, my answer is as follow: $$P = \epsilon_{0} X E = (\epsilon-\epsilon_{0}) E; \space \space \space \space \space \space \space E = P/(\epsilon-\epsilon_{0})$$
 
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Herculi said:
Homework Statement:: ...
Relevant Equations:: ...

View attachment 282969

I am a little confused why my answer is wrong... Briefly, my answer is as follow: $$P = \epsilon_{0} X E = (\epsilon-\epsilon_{0}) E; \space \space \space \space \space \space \space E = P/(\epsilon-\epsilon_{0})$$
Disclaimer: all I know about this topic is from two minutes' web search.
Are you perhaps confusing the applied field with the local field?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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