Why is My Polarized Plate Field Calculation Incorrect?

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SUMMARY

The discussion centers on the incorrect calculation of the polarized plate field, specifically the relationship between polarization (P), permittivity (ε), and the electric field (E). The user presented the equation $$P = \epsilon_{0} X E = (\epsilon-\epsilon_{0}) E$$ and derived $$E = P/(\epsilon-\epsilon_{0})$$. A key point raised in the discussion is the potential confusion between the applied electric field and the local electric field, which is crucial for accurate calculations in electrostatics.

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Relevant Equations
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I am a little confused why my answer is wrong... Briefly, my answer is as follow: $$P = \epsilon_{0} X E = (\epsilon-\epsilon_{0}) E; \space \space \space \space \space \space \space E = P/(\epsilon-\epsilon_{0})$$
 
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Herculi said:
Homework Statement:: ...
Relevant Equations:: ...

View attachment 282969

I am a little confused why my answer is wrong... Briefly, my answer is as follow: $$P = \epsilon_{0} X E = (\epsilon-\epsilon_{0}) E; \space \space \space \space \space \space \space E = P/(\epsilon-\epsilon_{0})$$
Disclaimer: all I know about this topic is from two minutes' web search.
Are you perhaps confusing the applied field with the local field?
 

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