Use your definitions. Kinetic friction is dependent on four things: The mass of the object, the magnitude of local gravity conditions (little g), the coefficient of kinetic friction, and any extra force in the y direction. We know little g is 9.8 meters per second squared (assuming this question wasn't one of those alien planet questions). Do we know the masses of the objects? If not, are they all the same mass? Can we assume that all the coefficients of kinetic friction are the same?
From the problem definition, we know that one of the boxes has extra force in the y direction, while one of the boxes does not. The extra force in the y direction, depending on whether it worked with gravity (pushed down on the box) or against gravity (pulled up on the box), would affect the normal force acting on the box. Use the fact that force is a vector quantity to separate it into its x and y components. For the horizontal force, this is unnecessary because all the force is in the x direction. For the funny one at an angle, you need to separate it into its components using vector algebra.
So, if you have three boxes of equal mass (m1=m2=m3), all of the same material and on the same surface (μk1=μk2=μk3, or in other words all the coefficients of kinetic friction are the same), and they're all in the same gravity field (Earth's), then the only possible difference can come from the direction in which the equal force is applied. Thus, the box with the greatest kinetic friction is going to be the box whose force vector is directed downwards (with gravity, thereby increasing the acceleration, thus increasing the normal force, thus increasing the kinetic friction), and the one with the least kinetic friction is going to be the one whose force vector is directed upward (against gravity, thereby counteracting some of the acceleration, thus reducing the normal force, thus reducing the kinetic friction).
Hope this helps.