Why is the boiling point elevation of NaCl solution higher than calculated?

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Discussion Overview

The discussion revolves around the boiling point elevation of a NaCl solution, specifically why the observed boiling point elevation is higher than the calculated value. It includes aspects of molecular interactions, dissociation of ions, and the assumptions of ideal solutions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the molecular description of boiling point elevation, suggesting it may relate to breaking ligand bonds between water and salt during evaporation, but acknowledges the endothermic nature of dissolving NaCl.
  • Another participant inquires about the effect of NaCl on vapor pressure, noting that the normal boiling point is defined where vapor pressure equals 1 atm.
  • Several participants emphasize the importance of considering dissociation of NaCl into Na+ and Cl- ions when calculating boiling point elevation.
  • One participant mentions the Van 't Hoff factor (i) in relation to osmotic pressure, indicating that it accounts for the number of particles the solute dissociates into.
  • A later reply expresses urgency regarding the report submission, reiterating the original question about the discrepancy in boiling point elevation.

Areas of Agreement / Disagreement

Participants express uncertainty about the calculations and the role of dissociation, with no consensus reached on the reasons for the observed boiling point elevation being higher than calculated.

Contextual Notes

The discussion highlights the assumption of ideal solutions in the boiling point elevation equation and the potential limitations of this assumption when dealing with ionic compounds like NaCl.

jimRH9
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Hullo. I'm doing a lab report on boiling point elevation, and we have to answer the question: "the boiling point elevation is higher than the calculated value, Why?". as a question on the side.

In the experiment, the solution is 30g/l NaCl in water.
The equation used to calculate the calculated value is Boiling point elevation = Molal elevation const. x Molality.
Molal elevation const = 0.52

I'm looking for some kind of molecular description, I thought it might be to do with breaking ligand bonds between the water and the salt during evapouration, but dissolving NaCl is endothermic (according to wikipedia~~~), plus i don't think it would have that effect until you boil it dry.

I know the equation assumes it's an ideal solution, and it's not cos NaCl is ionic, what can't explain is why the boiling point elevation would be more than the calculated value, rather than just different from it...

any help greatly apprecaited, thanks.
 
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Wht happens to the vapour pressure when NaCl is added to water?Does it increase or decrease?Then remember tht the definition of the normal boiling point is where the vapour pressure equals 1 atm.
Btw this is the wrong place to ask such questions...this is a chemistry question
 
Dissociation taken into account?

Boiling point elevation is taught at chemistry lessons, but I have problems classifying it as a just a chemistry subject.
 
Borek said:
Dissociation taken into account?

Boiling point elevation is taught at chemistry lessons, but I have problems classifying it as a just a chemistry subject.

Borek
--
Sorry, i posted it in a rush. Can I move it myself, Or does a moderator have to do it?
 
Don't worry, if one of Mentors will decide to, they'll move the thread.

Have you taken dissociation into account?
 
Borek said:
Don't worry, if one of Mentors will decide to, they'll move the thread.

Have you taken dissociation into account?

I'm not really sure what you mean, I know what dissociation is I know the salt forms Na+ and Cl- in water, but there's nothing about that in the equation...
 
The equation of osmotic pressure is equal to iMRT...i is the vant hoff factor i.e. the number of particles it dissociates into.
 
Sorry to bump my own thread, but this report has to be in for 2 tommorow, and I've got lectures all day, so it is a matter of some urgency.

jimRH9 said:
what i can't explain is why the boiling point elevation would be more than the calculated value, rather than just different from it...
QUOTE]

I don't know if I really made it clear, but this is the question i was asking.
 
Everything you need was already listed in terminator88 and my posts.
 
  • #10
k it seeems u r not reading wht I have said...
 
  • #11
ach, It doesn't matter, I handed in the report today anyway. Thanks anyway.
 

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