Why is the decay of Rho meson into pion and photon suppressed?

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The decay of the Rho meson ($\rho^0$) into a pion ($\pi^0$) and a photon ($\gamma$) is significantly suppressed due to the nature of the interactions involved. The Particle Data Group (PDG) indicates that this decay occurs with a branching ratio of approximately $\Gamma_i/\Gamma \sim 4.5\cdot 10^{-4}$, highlighting its rarity. The primary reason for this suppression is that the decay proceeds via electromagnetic (EM) interactions rather than the favored strong interaction, which is responsible for the more common decay mode $\rho^0\rightarrow \pi^+\pi^-$. Additionally, at the lowest order in chiral perturbation theory, there are no tree-level diagrams available for this decay.

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benjammin
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Does anyone know why the $$\rho^0\to\pi^0\gamma$$ decay is suppressed? I've been working on it, and so far I think it can conserve parity, charge conjugation, angular momentum, etc. But the PDG indicates that it basically never happens. Why?

Thanks!
 
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Unless there's something deeper I'm missing, I assume its due to the neutral nature of each meson. At lowest order in chiral perturbation theory there are no tree level diagrams for this decay.

Benjammin, are you from Detroit by any chance? (Don't have to answer publicly)
 
\Gamma_i/\Gamma \sim 4.5\cdot 10^{-4} is far different from "basically never happens." \rho^0\rightarrow \pi^+\pi^- is favored because it can proceed via the strong interaction. \rho^0\rightarrow \pi^0\gamma is primarily EM.
 

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