Why is the direction of temperature gradient important in thermal conductivity?

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Homework Help Overview

The discussion revolves around thermal conductivity and the significance of the temperature gradient in relation to heat flow direction. Participants are exploring the implications of how temperature differences are calculated in different scenarios.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the calculation of temperature differences (ΔΘ) in various examples and discussing the physical significance of the sign of the temperature gradient (dθ/dx). There is an exploration of whether the choice of reference points (hot and cool ends) affects the outcome.

Discussion Status

Some participants have provided insights into the nature of the temperature gradient and its relation to heat flow direction. There is an ongoing exploration of different interpretations regarding the calculation of temperature differences, but no explicit consensus has been reached.

Contextual Notes

Participants are considering the implications of different reference points for temperature measurements and how these affect the sign of the temperature gradient. The discussion is framed within the context of thermal conductivity and its principles.

Ronaldo95163
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I'm doing Thermal conductivity and I'm kinda confused on something wrt to the temperature gradient...why is it that ΔΘ in the first case the smaller value minus the larger but in the second example it's the larger minus the smaller?
 

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Ronaldo95163 said:
I'm doing Thermal conductivity and I'm kinda confused on something wrt to the temperature gradient...why is it that ΔΘ in the first case the smaller value minus the larger but in the second example it's the larger minus the smaller?
Whether dθ/dx is positive or negative has no physical significance. Heat flow is always from hotter to cooler. The sign depends on where you put the origin and where the hot end is in relation to the origin.

AM
 
Oh cool
So For the first example it wouldn't have mattered if 120-0 was used instead then?
 
Ronaldo95163 said:
Oh cool
So For the first example it wouldn't have mattered if 120-0 was used instead then?
If the hot end is at the origin (x=0) and the cool end at x=20cm then:

dθ/dx = Δθ/Δx = (0-120)/(20-0) = -6°/cm

If the cool end is at the origin (x=0) and the hot end at x=20cm then:

dθ/dx = Δθ/Δx = (120-0)/(20-0) = 6°/cm

The gradient from hot to cold is always negative: i.e. temperature decreases with distance from the hot end.

AM
 
Thanks a lot man :D
 

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