why do electric field is zero out side of depletion region?
In an area with charge carriers, how could there be a permanent electric field without current flow?
can you explain it with using of coulomb rule?
This is simple U=RI with negligible I and finite R. The Coulomb rule is not useful here.
in depletion layer there are uncovered charges that generate electric field , how cancel their field?
The remaining atoms have a charge as well. There is nothing "uncovered". A doped semiconductor has free charges of one type with zero overall charge density. If you remove those free charges the volume gets charged.
the remaining atom dont generate any fied, then who cancel the field of depletion layer?
Sure they do.
Replace a silicon atom with boron. It has one electron and one proton less, so the overall charge is zero - but now you have a hole because another electron can bind there easily. If you fill the hole you have a negative charge.
Replace a silicon atom with phosphorus. It fits in the crystal structure but has a 5th valence electron, while the overall charge is still zero - but now you have an electron that will easily leave its spot. If you remove the free electron you have a positive charge.
if for each atom the overall charge is zero, then they dont generate any fied.
And that's exactly what you have outside the depletion region.
but who cancel the field of depletion layer?
The other half of the depletion layer.
it is not correct,
the other half is more far
then it can not cancel the field of opposite half
Distance does not matter in a one-dimensional problem. Sheets of uniform charge density lead to uniform fields in all space (outside those sheets).
sheets of uniform charge must have infinite dimension(infinite plane) to lead uniform fields
in pn junction there is not infinite sheet
then distance matter
Compare the typical thickness of a depletion region with the typical dimension of a semiconductor device.
The infinite sheet is a good approximation unless you consider modern microprocessors, and then things are much more complicated anyway.
i dont talk about approximation
i talk about exact situation
Your statement in post 1 is an approximation.
Actually, every description you will ever see is an approximation. Just the quality is different.
actually, in non ideal diode electric field is zero outside of depletion region.
this is exact not approximation.
- The electric field is never exactly zero anywhere.
- Charge distribution is never exactly uniform in space
- the depletion layer does not have an exact boundary
Separate names with a comma.