pyctz
- 18
- 0
why do electric field is zero out side of depletion region?
The discussion revolves around the behavior of the electric field outside the depletion region in semiconductor physics, exploring the underlying principles and mechanisms that lead to a zero electric field in that area. Participants engage in technical reasoning, challenge each other's claims, and explore the implications of charge distributions and approximations in the context of semiconductor devices.
Participants express multiple competing views regarding the behavior of electric fields in the depletion region and outside of it. There is no consensus on the applicability of approximations or the exact nature of charge distributions and their effects on the electric field.
Limitations include the dependence on idealized models and approximations, as well as the complexity introduced by real-world semiconductor structures that may not conform to simplified theoretical descriptions.
can you explain it with using of coulomb rule?mfb said:In an area with charge carriers, how could there be a permanent electric field without current flow?
in depletion layer there are uncovered charges that generate electric field , how cancel their field?mfb said:This is simple U=RI with negligible I and finite R. The Coulomb rule is not useful here.
the remaining atom don't generate any fied, then who cancel the field of depletion layer?mfb said:The remaining atoms have a charge as well. There is nothing "uncovered". A doped semiconductor has free charges of one type with zero overall charge density. If you remove those free charges the volume gets charged.
Sure they do.pyctz said:the remaining atom don't generate any fied
if for each atom the overall charge is zero, then they don't generate any fied.mfb said:Sure they do.
Replace a silicon atom with boron. It has one electron and one proton less, so the overall charge is zero .
but who cancel the field of depletion layer?mfb said:And that's exactly what you have outside the depletion region.
it is not correct,mfb said:The other half of the depletion layer.
sheets of uniform charge must have infinite dimension(infinite plane) to lead uniform fieldsmfb said:Distance does not matter in a one-dimensional problem. Sheets of uniform charge density lead to uniform fields in all space (outside those sheets).
i don't talk about approximationmfb said:Compare the typical thickness of a depletion region with the typical dimension of a semiconductor device.
The infinite sheet is a good approximation unless you consider modern microprocessors, and then things are much more complicated anyway.
actually, in non ideal diode electric field is zero outside of depletion region.mfb said:Your statement in post 1 is an approximation.
Actually, every description you will ever see is an approximation. Just the quality is different.
inside a conductor The electric field is exactly zeromfb said:- The electric field is never exactly zero anywhere.
- Charge distribution is never exactly uniform in space
- the depletion layer does not have an exact boundary
- ...
All approximations.
if The electric field is not zero the free charges move until it becomes zeromfb said:Not exactly.
As I said, those statements are all approximations.
In the real world, physics is never exact.
if The electric field is not zero the free charges move until it becomes zeromfb said:Not exactly.
As I said, those statements are all approximations.
In the real world, physics is never exact.