Why is the function f(z) = ¯z not differentiable for any z ∈ C?

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Homework Help Overview

The discussion revolves around the differentiability of the function f(z) = ¯z in the context of complex analysis. Participants are exploring why this function is not differentiable for any z in the complex plane.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Some participants reference the Cauchy-Riemann equations as a potential reason for the lack of differentiability. Others suggest using the definition of the derivative to analyze the limit behavior of the function when approached from different directions in the complex plane.

Discussion Status

Participants are actively engaging with the problem, considering different approaches to demonstrate the non-differentiability of the function. There is a recognition that the limits yield different results depending on the direction of approach, indicating a productive exploration of the topic.

Contextual Notes

Some participants note that the Cauchy-Riemann equations were learned later in their studies, which may influence their approach to the problem. There is also an acknowledgment of the definition of the derivative as a viable method for analysis.

Applejacks
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Homework Statement



Show that f(z) = ¯z is not differentiable for any z ∈ C.

Homework Equations


The Attempt at a Solution



Is it because the Cauchy-Reimann Equations don't hold?

Z (conjugate) = x-iy
u(x,y)=x
v(x,y=-iy

du/dx=1≠dv/dy=-1
du/dy=0≠-dv/dx=0
Edit: Is there another approach? Because the CR Equations is something we learned later on.
 
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Applejacks said:

Homework Statement



Show that f(z) = ¯z is not differentiable for any z ∈ C.

Homework Equations


The Attempt at a Solution



Is it because the Cauchy-Reimann Equations don't hold?

Z (conjugate) = x-iy
u(x,y)=x
v(x,y=-iy

du/dx=1≠dv/dy=-1
du/dy=0≠-dv/dx=0
Edit: Is there another approach? Because the CR Equations is something we learned later on.

Sure. Use the definition of f'(z)=lim h->0 (f(z+h)-f(z))/h. Show the limit is different if you pick h to be real from the limit if you pick h to be imaginary. That's really what the content of the CR equations is.
 
Last edited:
I think I get it now.

(f(z+h)-f(z))/h

(conjugate((z+h)-z))/h = h(conjugate)/h

If h=Δx, the ratio equals 1
If h=Δiy, the ratio equals -1.

Since the two approaches don't agree for any z, z(conj) is not analytic anywhere. Correct?
 
Applejacks said:
I think I get it now.

(f(z+h)-f(z))/h

(conjugate((z+h)-z))/h = h(conjugate)/h

If h=Δx, the ratio equals 1
If h=Δiy, the ratio equals -1.

Since the two approaches don't agree for any z, z(conj) is not analytic anywhere. Correct?

Yep, that's it. That's how you derive CR.
 

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