Why is the limit of cot(x) approaching pi from the negative side -infinity?

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Homework Help Overview

The discussion revolves around the limit of cotangent as x approaches pi from the negative side, specifically evaluating the expression lim x->pi- cot(x). Participants are exploring the behavior of cot(x) near this limit and the implications of substituting values into the cotangent function.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to evaluate the limit by substituting pi into the cotangent function and question the resulting sign of infinity. There is also a comparison made with another limit involving a rational function, leading to confusion about the signs of the limits.

Discussion Status

Some participants have provided insights into the behavior of the sine function near pi, which has helped clarify the reasoning behind the limit approaching negative infinity. However, there remains a focus on understanding the underlying concepts rather than reaching a definitive conclusion.

Contextual Notes

Participants are grappling with the interpretation of limits involving division by zero and the signs of trigonometric functions in specific intervals. There is an acknowledgment of differing approaches to determining the sign of infinity in various limit scenarios.

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Homework Statement


lim x->pi- cot(x)


Homework Equations


cot(x) = cos(x)/sin(x)


The Attempt at a Solution



so substituting pi into:
cot(pi) = cos(pi)/sin(pi)
= -1/0
so you have a negative over 0, approaching from the -ve side of pi wouldn't it be +infinity? why is it -infinity?


additionally this confuses me because a previous question I was working went like:

1)lim x->-3+ (x+2)/(x+3) = - infinity
2)lim x->-3- (x+2)/(x+3) = + infinity
when substituting in 3, one would get a -ve int/0.
so i thought you found out whether it is +ve or -ve infinity by multiplying signs.
1) -3+ so take + times - (from -ve int) = -ve ...and you get -ve infinity
2) -3- so take - times - (from -ve int) = +ve ...and you get +ve infinity

but that was the way a friend showed me, its worked for all the questions up until the cotx one. any help in understanding is much appreciated, thanks.
 
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shocklightnin said:

Homework Statement


lim x->pi- cot(x)


Homework Equations


cot(x) = cos(x)/sin(x)


The Attempt at a Solution



so substituting pi into:
cot(pi) = cos(pi)/sin(pi)
= -1/0
so you have a negative over 0, approaching from the -ve side of pi wouldn't it be +infinity? why is it -infinity?


additionally this confuses me because a previous question I was working went like:

1)lim x->-3+ (x+2)/(x+3) = - infinity
2)lim x->-3- (x+2)/(x+3) = + infinity
when substituting in 3, one would get a -ve int/0.
so i thought you found out whether it is +ve or -ve infinity by multiplying signs.
1) -3+ so take + times - (from -ve int) = -ve ...and you get -ve infinity
2) -3- so take - times - (from -ve int) = +ve ...and you get +ve infinity

but that was the way a friend showed me, its worked for all the questions up until the cotx one. any help in understanding is much appreciated, thanks.
What is the sign of sin(x) when x is a little less than π ?
 
positive..?
 
Right, so it should be \frac{-1}{0^+} because we're looking at \sin(\pi ^-)
 
ooh right right! so that's why its -ve infinity. ah thanks, got it now :P
 

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