Why Is the Resultant Amplitude of Interfering Waves Not Simply A1 + A2?

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The resultant amplitude of two interfering waves is not simply A1 + A2 due to the phase difference between the waves. When waves are out of phase, their peaks do not align, preventing a direct addition of their amplitudes. The correct calculation involves using the cosine rule, which accounts for the phase angle difference. Only when the waves are in phase (θ = 0) can their amplitudes be added directly. Thus, the resultant amplitude is determined by the square root of the sum of the squares of the individual amplitudes.
desmond iking
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Homework Statement



when a point is intefered by 2 waves of different phase , the resultant is y1 + y2 ... but why the resultant amplitude can't be = A1 + A2 ... but is sqrt root ((A1)^2 + (A2)^2) ??

this is actually a online note.

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The Attempt at a Solution

 

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desmond iking said:
when a point is intefered by 2 waves of different phase , the resultant is y1 + y2 ... but why the resultant amplitude can't be = A1 + A2 ... but is sqrt root ((A1)^2 + (A2)^2) ??
It isn't, and your pic shows it isn't. The peak of the resultant amplitude is determined using the cosine rule and the phase angle difference. Only if the phase angle was 90 degrees would your equation using Pythagoras hold.
 
NascentOxygen said:
It isn't, and your pic shows it isn't. The peak of the resultant amplitude is determined using the cosine rule and the phase angle difference. Only if the phase angle was 90 degrees would your equation using Pythagoras hold.

sorry, i mean why can't i add up A1 and A2 to get the resultant amplitude... tHat means resultant amplitude =A1+ A2
 
Because y1 and y2 never reach their maximum values at the same time. unless they're in phase (θ = 0).
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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