Why Is the Schwarzschild Solution Considered Spatially Symmetric?

The notation SO(3) is used because the group consists of "special" orthogonal matrices, meaning that they have determinant 1 and thus do not reflect space. This is in contrast to the general orthogonal group O(3), which includes reflections.
  • #1
off-diagonal
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I've read Schwarzschild paper and I don't understand his conditions

"The solution is spatially symmetric with respect to the origin of the co-ordinate system in the sense that one finds again the same solution when x,y,z are subjected to an orthogonal transformation(rotation)"


Could anyone explain me about this??


Thank you
 
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  • #2
He's assuming spherical or rotational symmetry. In other words, the solution/metric does not depend on which direction you're looking in (from the origin). This is a reasonable assumption for the metric around a star, since stars are to a high degree "round" =)
 
  • #3
off-diagonal said:
"The solution is spatially symmetric with respect to the origin of the co-ordinate system in the sense that one finds again the same solution when x,y,z are subjected to an orthogonal transformation(rotation)"

Hi off-diagonal! :smile:

"orthogonal" means that it's a member of SO(3), the three-dimensional group of speical orthogonal transformations.

Basically, SO(3) means all rotations.

See http://en.wikipedia.org/wiki/Rotation_group for more details:
The rotation group is often denoted SO(3) for reasons explained below.
 

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