The actual values are opposite to your statement.
The specific heat capacity of ice is about half than the specific heat capacity of liquid water.
Copied from:
https://en.wikipedia.org/wiki/Specific_heat_capacity#Definition
"In thermodynamics, the specific heat capacity (symbol
c) of a substance is
the amount of heat that must be added to one unit of mass of the substance in order to cause an increase of one unit in temperature."
"For example, the heat required to raise the temperature of 1 kg of water by 1 K is 4184 joules, so the specific heat capacity of water is 4184 J⋅kg−1⋅K−1.
Specific heat capacity often varies with temperature and is different for each state of matter. Liquid water has one of the highest specific heat capacities among common substances, about 4184 J⋅kg−1⋅K−1 at 20 °C; but that of ice, just below 0 °C, is only 2093 J⋅kg−1⋅K−1."
If the rate at which the substance absorbs heat is constant, the phase having a lower value of specific heat capacity (less heat needed "to cause an increase of one unit in temperature") should show a steeper slope in a temperature-versus-time diagram.
In practical terms, it is quicker to provide certain ΔT to a mass of ice than similar ΔT to the same mass of water, having the same source of heat for both.
Therefore, the text in the book is correct: "the line for the solid phase (ice) has a steeper slope than does the line for the liquid phase (water)."
I believe that the line that represents heating of the gaseous phase in the posted diagram should be steeper than the line representing heating water, as the specific heat of steam oscillates between 1.5 and 2.3.
Please, see:
https://www.engineeringtoolbox.com/specific-heat-capacity-gases-d_159.html