Why is the system considered linear in this case?

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The discussion centers on the linearity of a system defined by the equation y(t) = [cos(3t)] * x(t). The user presents a scenario with inputs x1(t) and x2(t), leading to outputs y1(t) and y2(t). The confusion arises when combining inputs x1(t) and x2(t) to form x3(t), resulting in an output y3(t) that does not satisfy the linearity condition y3(t) = a*y1(t) + b*y2(t). Ultimately, the user acknowledges a mistake in their reasoning, confirming that the system is indeed linear as stated in the reference material.

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khdani
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hello,
y(t)=[cos(3t)]*x(t)
x1(t) -> y1(t)=[cos(3t)]*x1(t)
x2(t) -> y2(t)=[cos(3t)]*x2(t)
x3(t) = a*x1(t)+b*x2(t)
x3(t) -> y3(t)=[cos(3t)]*x3(t)=[cos(3t)]*(a*x1(t)+b*x2(t))=
=[cos(3t)]*(a*[cos(3t)]*x1(t)+b*[cos(3t)]*x2(t))
y3(t) not equal a*y1(t)+b*y2(t) but the answers in the book said that
the system is linear? why? am i wrong or there's a mistake in the book?
 
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Check out the last two lines again. You've got a mistake there...
 
i found the mistake, thanks
 

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