Is a nth order ODE considered linear if n=2?

  • Thread starter Thread starter Saladsamurai
  • Start date Start date
  • Tags Tags
    Linearity
Click For Summary

Homework Help Overview

The discussion revolves around the classification of nth order ordinary differential equations (ODEs) as linear or non-linear, specifically focusing on the case when n=2. Participants explore the definitions of order and degree in the context of differential equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants clarify the distinction between the order of derivatives and their degree in equations. They discuss examples of linear and non-linear equations, questioning the implications of raising terms to powers greater than one.

Discussion Status

Some participants have provided clarifications regarding the definitions involved, noting that the linearity of an equation depends on the degree of the dependent variable and its derivatives. There is ongoing exploration of the implications of different forms of equations, including the role of constants on the right-hand side.

Contextual Notes

Participants are examining specific examples and definitions from their differential equations textbook, indicating a focus on understanding the foundational concepts rather than solving specific problems.

Saladsamurai
Messages
3,009
Reaction score
7
I am reading through my Diff Eqs Text and I follow most of the lingo. However I am just a tad confused by the statement:

An nth order ODE is said to be linear if F is linear in y,y',...y^(n)

Then it gives the example:

a_n(x)\frac{d^ny}{dx^n}+a_{n-1}(x)..+a_0(x)y=g(x)

It then says: 'On the left-hand side of the above equation the dependent variable y and all of its derivatives, y,y',y'',...y^n are of the first degree.

Clearly I missed something in Calc. If n=2, I have: \frac{d^2y}{dx^2}

Why is this linear if n=2?

Thanks,
Casey
 
Physics news on Phys.org
You're confusing the *order* of the derivative with its *degree* in the equation.

y'' + y = 0

is a second-order linear equation. Second-order because the highest order derivative in the equation is a second dervative. Linear because the equation itself is linear in both y'' and y.

In contrast:

(y'')^2 + ay^3 = 0

is a second-order NON-linear D.E. Second-order for the same reason. NON-linear because it is QUADRATIC in y'' and CUBIC in y. I hope this clears things up.
 
Last edited:
cepheid said:
You're confusing the *order* of the derivative with its *degree* in the equation.

y'' + y = 0

is a second-order linear equation. Second-order because the highest order derivative in the equation is a second dervative. Linear because the equation itself is linear in both y'' and y.

In contrast:

(y'')^2 + ay^3 = 0

is a second-order NON-linear D.E. Second-order for the same reason. NON-linear because it is QUADRATIC in y'' and CUBIC in y. I hope this clears things up.

I think it does. y' just means "the 1st derivative" and similarly for y" however if either one y' or y" or y for that matter were raised to any power above 1, the DE would no longer be linear.

Thanks!
 
Yes, that is correct. Also note that other "non-linear" functions of the dependent variable, y or its derivatives, such as sin(y) or exp(y"), would make the equation non-linear.
 
HallsofIvy said:
Yes, that is correct. Also note that other "non-linear" functions of the dependent variable, y or its derivatives, such as sin(y) or exp(y"), would make the equation non-linear.

Great, thanks Halls and cepheid. Hey also, I know that the right-hand side can be equal to 0 or a function of the independent variable; what about a constant?

Like \frac{d^2y}{dx^2}-\frac{dy}{dx}+6y=7 ?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
6
Views
2K
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K