Why is the threshold for triplet production 4m0c^2?

  • Context: Graduate 
  • Thread starter Thread starter coregis
  • Start date Start date
  • Tags Tags
    Threshold
Click For Summary
SUMMARY

The threshold for triplet production is established at 4m0c² due to the conservation of energy and momentum principles in particle physics. In this context, the equation m(e)c² + hv = 3m(c²) illustrates the energy balance required for the production of three particles, including an electron and positron pair. The calculations reveal that the momentum conservation necessitates additional energy, leading to the conclusion that a photon must possess energy equivalent to 4m0c² to facilitate this process. The Feynman diagrams referenced provide a visual representation of these interactions.

PREREQUISITES
  • Understanding of conservation laws in physics, specifically conservation of energy and momentum.
  • Familiarity with particle physics concepts, including electron and positron production.
  • Knowledge of Feynman diagrams and their application in visualizing particle interactions.
  • Basic grasp of relativistic energy equations, particularly E=mc².
NEXT STEPS
  • Study the derivation of the threshold energy for particle production in quantum field theory.
  • Explore Feynman diagrams in detail to understand complex particle interactions.
  • Investigate the implications of conservation laws in high-energy physics experiments.
  • Review the role of momentum conservation in photon interactions with matter.
USEFUL FOR

This discussion is beneficial for physicists, students of particle physics, and researchers interested in the mechanics of particle production and conservation laws in high-energy interactions.

coregis
Messages
17
Reaction score
0
I can understand why the threshold for pair priduction is 2m0c^2. But why is the threshold for triplet production 4m0c^2? Thanks.
 
Physics news on Phys.org
If you're talking about photon to electron/positrons, then the reason is because electrons and positrons are always produced in pairs (conservation of electric charge, for instance). A triplet production includes one electron/positron that has so little momentum that it is missed.

The Feynman diagrams on page 4 of this paper will show what is going on:
http://arxiv.org/PS_cache/hep-ph/pdf/9909/9909323.pdf

Carl
 
Last edited by a moderator:
for triplet production conservation of energy is;

m(e)c2+hv=m(b+)c2+m(b-)c2+E(kinetic energy of participating electron on left side of equation)
Now assume that elctron was at rest so m(e)c2=_m(0)c2 and E= mc2 and also they (triplets)are more probabilistic to take equal E(K)
so above eq becomes
m(0)c2+hv=3mc2
and per conservation of momentum we have
hv/c=3mv=3mBc (B=v/c)

solving above 2 eq in B gives
(1-B2)1/2+3B=3 and that gives B=4/5
=give m=m(0)*5/3
now putting m value in momentum eq we get
hv=3*5/3*m(0)*4/5*c2=4m(0)c2
And this is due to conservation of momentum of photon as without third particle either e or nucleus this process is impossible as photon momentum is not conserved and as elctron rest mass is small it need more energy than pair production do, to physically this process to occur.
now i suppose that it will clear the threshold requirment
 
how did you find the value of B, i mean please show how B=4/5. I couldn't understand that step!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K