Why is there a -1/2 in the Lagrangian density for ω mesons?

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SUMMARY

The discussion centers on the inclusion of the -1/2 factor in the Lagrangian density for ω mesons. Participants confirm that this factor is necessary for maintaining the correct sign for the kinetic and mass terms when using the east-coast metric, specifically where the metric tensor is defined as ημν = diag(1, -1, -1, -1). The physical degrees of freedom for the ω meson are three spatial vectors, which further necessitates the presence of the -1/2 term to ensure accurate representation of the meson's properties.

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  • Concept of physical degrees of freedom in particle physics
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izzi wekwek
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My question is why there is -1/2 for ω meson?
 
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Where did you find these lagrangians?
I would remove the (-)1/2( ...) bit.
Then it can be correct if σ is complex and ω is real valued.
 
No, you shouldn't remove the ##-1/2## ;-), because it's correct. You obviously work in the east-coast metric, where ##(\eta_{\mu \nu})=\mathrm{diag}(1,-1,-1,-1)##. The physical degrees of freedom of ##\omega^{\mu}## are three space like vectors, and thus to get the right sign for the kinetic and the mass term there must be that additional - sign.
 

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