Why is there are precession frequency here?

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SUMMARY

The discussion centers on the precession frequency of a spinning rod and its interaction with a disk, specifically using the equation omega_pr = mgr / L_s with a radius (r) of 6 cm. The user questions how precession occurs when the rod pierces the disk through the middle, suggesting that weight does not generate torque to induce a horizontal change in angular momentum. Additionally, the impact of a slightly tipped axis of rotation and an uneven surface on the spinning toy's behavior is explored.

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Homework Statement
A child's toy top consists of a uniform thin disk of radius 5.0 cm and mass
0.15 kg with a thin spike passing through its center. The lower part of the
spike protrudes 6.0 cm from the disk. If you stand this top on a table and start
it spinning at 200 rev/s, what will be its precession frequency?
Relevant Equations
.
so I need to use the eq.: omega_pr = ##mgr / L_s## with r = 6cm.
But from how I imagine/see it, the rod pierces the disk through the middle so how does this create precession if the weight will not cause a torque then and thus a hortizontal change in angular momentum?

Thanks in advance!
 
Physics news on Phys.org
What if the axis of rotation is slightly tipped when the toy is started spinning? What if the surface on which it is spinning is not exactly flat? You get the point.
 

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