Why isn't radius of curvature at max height just the maximum height?

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vipulgoyal
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Homework Statement



a stone is projected at an angle with the horizontal with velocity u. it executes a nearly circular motion near its maximum height for a short time. the radius of circular path is
??`

Homework Equations


answer is u2 sin2x/g3. The Attempt at a Solution
why isn't it is just the maximum height?
 
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vipulgoyal said:
why isn't it is just the maximum height?

I can't understand what you are asking
 


cupid.callin said:
I can't understand what you are asking

i just want to know the radius of the circular path exhibited by the stone at the top of its path

""why it isn't the maximim height"" i mean that answer should be the mximum height attained by the body
 


no it won't be max height

like in this case:

attachment.php?attachmentid=33448&stc=1&d=1300916524.gif


H is max height but radius is R
 
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cupid.callin said:
no it won't be max height

like in this case:

attachment.php?attachmentid=33448&stc=1&d=1300916524.gif


H is max height but radius is R

yeah... thnx

but still don't know how to find R ??
 


(Its late now ... must sleep or take steroids :zzz:)

use the eqn:

[tex]a_{radial} = \frac{v^2}{Radius}[/tex]

and here v will be tangential to the curve obviously

(off to sleep :zzz:)
 
hi vipulgoyal! :smile:

it is asking you for the radius of curvature at the top

hint: what is the speed at the top? :wink:​