Why multiply both sides by (3-x)(x+2) in 2x+9/((3-x)(x+2)) < 0

[MrNeWBiE]

question in fractions,,,

how

2x+9/(3-x)(x+2) < 0

became



(3-x)(x+2)(2x+9) < 0 " multiply both sides "

zero is in the other side ,,,

 

[tiny-tim]

Hi MrNeWBiE!

'cos one is (3-x)²(x+2)² times the other … which is always positive!

 

[MrNeWBiE]

so i multiply both sides with ====> (3-x)^2(x+2)^2

 

[tiny-tim]

(try using the X² tag just above the Reply box )

Yup!