the exersice is from stewart's book Ch 5.4 #3(adsbygoogle = window.adsbygoogle || []).push({});

i have the function [tex] y = \frac{x}{a^2 \sqrt(a^2-x^2)} [/tex]

this can be simplified like this

[tex] y = c*R(x) [/tex]

where R(x) = P(x)/Q(x) my question is

in the step of -P(x)*Q'(x) why is not zero????

if the formula says [tex] U^n = nU^n ^(-1) du [/tex]

in the exaple would be [tex] U^n = nU^n ^(-1) du [/tex]

(everything)*(2a*0+2x*1) so that zero makes all zero!!

so our answer is [tex] y' = \frac{1}{a^2 \sqrt(a^2-x^2)} [/tex], doesnt it?

i saw the real answer and its [tex] y' = \frac{1}{\sqrt((a^2-x^2))^3} [/tex]

im i wrong in the formula that i use for [tex] U^n [/tex]

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# Homework Help: Why? Question about Differentiation Exersice.

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