Why should Hawking radiation decrease a black hole's size?

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SUMMARY

The discussion centers on the concept of Hawking radiation and its effect on black hole mass. When particle-antiparticle pairs are created near a black hole's event horizon, one particle can be absorbed by the black hole while the other escapes as radiation. This process results in a net loss of mass for the black hole, as described by the equation E = mc². The energy required to create these virtual particles effectively reduces the black hole's mass over time, as only one particle contributes to the mass of the black hole.

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nhmllr
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So from what I understand when the particle anti-particle pairs that are constantly being created and annihilated come into existence near a black hole's horizon, the nearer one can get sucked in while the further one can radiate off as though it were heat. And this radiation of energy decreases that black holes mass over time, because of E = mc2

But what about the other particle that went into the singularity. Shouldn't the mass increase?

Thanks.
 
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The creation of a virtual pair of particles takes enough energy from the black hole to create them. Since only one of the pair falls back in, half of the stolen energy has now been permanently lost from the black hole.
 
Drakkith said:
The creation of a virtual pair of particles takes enough energy from the black hole to create them. Since only one of the pair falls back in, half of the stolen energy has now been permanently lost from the black hole.

Ohh... that kinda makes sense. Wow, that actually makes a lot of sense. Thanks.
 

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