Why using diff. forms in electromagnetism?

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Differential forms in electromagnetism, represented as F = Fμνdxμ ∧ dxν, provide a concise way to express Maxwell's equations. The homogeneous equations can be simplified to dF = 0, indicating that F is a closed form, which by the Poincaré lemma implies F can be expressed as the exterior derivative of a 1-form A, the 4-potential. This formulation facilitates the application of Stokes' theorem, enhancing the elegance and utility of Maxwell's equations. Additionally, using differential forms is crucial in modern physics, particularly in gauge field theory and general relativity. Overall, this approach offers both mathematical elegance and practical advantages in theoretical physics.
christianpoved
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In electromagnetism we introduce the following differential form
\begin{array}{c}
\mathbb{F}=F_{\mu \nu}dx^{\mu}\wedge dx^{\nu}
\end{array}
Then the homogeneus Maxwell equations are equivalent to:
\begin{array}{c}
d\mathbb{F} = 0
\end{array}
And is nice, but what purpose does this have?, there is something interesting in saying that F is a closed form?
 
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By the Poincare lemma, if ##dF = 0## then (at least locally) ##F = dA## for some 1-form ##A##; ##A## is of course none other than the 4-potential. This is why we can describe electromagnetism using the 4-potential.

Also, writing down Maxwell's equations as ##dF = 0## and ##d{\star}F = {\star}j## allows us to easily use Stokes' theorem ##\int_{\Omega}d\omega = \int _{\partial \Omega} \omega## when needed. There are other uses of course of writing down Maxwell's equations as ##dF = 0## and ##d{\star}F = {\star}j## (one of them being pure elegance!) and you will see the above form a lot in gauge theoretic treatments.
 
Differential forms are at the heart of modern physics, expecially gauge field theory (for which vacuum classical electrodynamics is the simplest case). And GR looks spectacular in terms of forms.
 

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