Why Velocity is different in different equations?

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In summary, the conversation discusses how to calculate velocity given a position and time. It includes equations for position and velocity, as well as a discussion on average speed and average velocity. There is also a question about why there are different results when using different equations.
  • #1
Gjmdp
148
5

Homework Statement


Calculate velocity. x=position. t=time

Homework Equations


x=16-12t+2(t^2)

The Attempt at a Solution


Derivative of x: v=4t-12
Ok let's try:
Equation of x: x=16-12t+2(t^2)
Equation of v: v=4t-12

With the equation of x: x(3)=-2 then v(3)=-2/3.
Ok, but with the equation of v: v(3)=0.
There are different results! Why?
What am I doing wrong?
 
Last edited:
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  • #2
Gjmdp said:

Homework Statement


Calculate velocity. x=position. t=time

Homework Equations


x=16-12t+2(t^2)

The Attempt at a Solution


Derivative of x: v=4t-12
Ok let's try:
Equation of x: x=16-12t+2(t^2)
Equation of v: v=4t-12

With the equation of x: x(3)=2 then v(3)=3/2.
Ok, but with the equation of v: v(3)=0.
There are different results! Why?
What am I doing wrong?
Using your equations: x(3)=16-12*3+2*9=16-36+18=-2 and v(3)=0.
How do you get v(3)=3/2?
 
  • #3
Samy_A said:
Using your equations: x(3)=16-12*3+2*9=16-36+18=-2 and v(3)=0.
How do you get v(3)=3/2?
So x(3)=-2 in t=3.
v=x/t
v(3)=-2/3
Sorry, I was wrong.
But it keep being different
v(3)=0: v(3)=-2/3
 
  • #4
Gjmdp said:
So x(3)=-2 in t=3.
v=x/t
v(3)=-2/3
I was wrong.
But it keep being different
v=0: v=-2/3
You are computing two different quantities.
The formula v=4t-12 gives you the velocity at t=3

The formula (distance travelled)/time would give you the average speed.
The formula (change in position)/time would give you the average velocity.
Try it out, by computing how much the traveling object has moved from t=0 to t=3, and then dividing this by 3. Take into account that x(0)≠0.
 
Last edited:
  • #5
-13/3 is the average speed from t=0 to t=3 OK thanks a lot.
 
  • #6
Gjmdp said:
-13/3 is the average speed from t=0 to t=3 OK thanks a lot.
How did you get -13?

Not saying it is wrong, but I find something different:
x(0)=16, x(3)=-2
Change in position=-2-16=-18
Average velocity = -18/3 =-6
 
  • #7
Gjmdp said:
So x(3)=-2 in t=3.
v=x/t
v(3)=-2/3
Sorry, I was wrong.
But it keep being different
v(3)=0: v(3)=-2/3
v is not equal to x/t. This is only correct if x =0 at t = 0 (which in your problem it is not) and if v is constant (which in your problem it is not).
 

Why is velocity different in different equations?

Velocity is defined as the rate of change of an object's position over time. Different equations may use different variables or assumptions, leading to different values for velocity.

What is the difference between average velocity and instantaneous velocity?

Average velocity is calculated by dividing the total displacement by the total time taken, while instantaneous velocity is the velocity at a specific moment in time. Average velocity is an overall measure, while instantaneous velocity provides information about an object's velocity at a specific point.

Why do some equations use velocity while others use speed?

Velocity is a vector quantity that includes both magnitude (speed) and direction. Some equations may only need to consider the magnitude, so they use the term speed instead of velocity.

How does acceleration affect velocity?

Acceleration is the rate of change of velocity over time. If an object experiences acceleration, its velocity will change. If the acceleration is in the same direction as the velocity, the object's speed will increase. If the acceleration is in the opposite direction, the object's speed will decrease.

Why is velocity often represented as a vector quantity?

Velocity involves both magnitude (speed) and direction, making it a vector quantity. Representing velocity as a vector allows us to easily calculate its components in different directions and analyze the motion of an object in a more comprehensive manner.

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