Why Wave Functions Use Complex Exponentials vs Trigonometric Functions

[redtree]

Why are wave functions, e.g., Schrodinger's, based on the complex exponential function (e^{}ix) and not trigonometric functions (sine or cosine)?

See Euler's formula for their relationship: http://en.wikipedia.org/wiki/Euler's_formula

Furthermore, by using the complex exponential function, the probability amplitude becomes a complex-valued function (a + bi). Were sine or cosine used, the probability amplitude of the wave function would not be a complex-valued function. Is there a reason that the probability amplitude should be a complex-valued function?

 

[Ben Niehoff]

You need complex-valued wavefunctions so that you can have standing waves of constant magnitude over time (such as in a potential well). Real-valued functions would have to oscillate in magnitude.

 

[redtree]

What do you mean by magnitude? Is it the same as amplitude?

 

[koolmodee]

Nothing keeps you from using sine and cos. That what Euler's identity says.

The time evolution of a state vector/ wave function must conserve the norm of the state vector, and it always has to be one.

Note e^{it} e^{it}=1.

 

[akhmeteli]

Why are wave functions, e.g., Schrodinger's, based on the complex exponential function (e^{}ix) and not trigonometric functions (sine or cosine)?

See Euler's formula for their relationship: http://en.wikipedia.org/wiki/Euler's_formula

Furthermore, by using the complex exponential function, the probability amplitude becomes a complex-valued function (a + bi). Were sine or cosine used, the probability amplitude of the wave function would not be a complex-valued function. Is there a reason that the probability amplitude should be a complex-valued function?

My post https://www.physicsforums.com/showpost.php?p=1539835&postcount=20 and some other posts in that thread may be relevant.

 

[dx]

The simple answer is that standard quantum mechanics as we understand it requires a complex wavefunction \psi defined on the configuration space. You can replace this with a function to \mathbb{R} \times \mathbb{R} and change the equations accordingly, since \mathbb{C} and \mathbb{R} \times \mathbb{R} are isomorphic. But you can't replace \psi with a function to just \mathbb{R}.

Also, Euler's formula doesn't turn a complex number into a real number. \cos \theta + i \sin \theta is still a complex number, and the probability amplitude will still be a complex valued function.

 

[redtree]

The simple answer is that standard quantum mechanics as we understand it requires a complex wavefunction \psi defined on the configuration space. You can replace this with a function to \mathbb{R} \times \mathbb{R} and change the equations accordingly, since \mathbb{C} and \mathbb{R} \times \mathbb{R} are isomorphic. But you can't replace \psi with a function to just \mathbb{R}.

What properties of standard quantum mechanics require a complex wavefunction?

 

[malawi_glenn]

The simple answer is that standard quantum mechanics as we understand it requires a complex wavefunction \psi defined on the configuration space. You can replace this with a function to \mathbb{R} \times \mathbb{R} and change the equations accordingly, since \mathbb{C} and \mathbb{R} \times \mathbb{R} are isomorphic. But you can't replace \psi with a function to just \mathbb{R}.QUOTE]


What properties of standard quantum mechanics require a complex wavefunction?

well the physics of spin 1/2 systems for example, see Sakurai - Modern Quantum Mechanics chapter 1

 

[dx]

What properties of standard quantum mechanics require a complex wavefunction?

That's like asking what property of Newtonian physics requires the mechanical state of a particle to be position and momentum. It is possible to construct a theory where the time evolution of a particle depends only on initial position, but that's not the way nature is. It just happens to be so that the mechanical state of a quantum system needed to predict future probabilities is a complex function.