Wick's Theorem Proof (Peskins and Schroder)

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SUMMARY

The discussion focuses on the induction proof of Wick's Theorem as presented by Peskins and Schroder. The key step under scrutiny involves the equality between two expressions involving normal ordering operators, specifically the transition from N(φ₂...φₘ)φ₁⁺ + [φ₁⁺, N(φ₂...φₘ)] to N(φ₁⁺φ₂...φₘ) + N([φ₁⁺, φ₂⁻]φ₃...φₘ + φ₂[φ₁⁺, φ₃⁻]φ₄...φₘ + ...). The resolution of this step relies on recognizing that φ₁⁺ is composed solely of annihilation operators and applying the commutation relation [A,BC] = [A,B]C + B[A,C] to facilitate the proof through induction.

PREREQUISITES
  • Understanding of quantum field theory concepts, particularly Wick's Theorem.
  • Familiarity with normal ordering notation and its significance in quantum mechanics.
  • Knowledge of commutation relations between operators in quantum mechanics.
  • Experience with mathematical induction as a proof technique.
NEXT STEPS
  • Study the derivation of Wick's Theorem in "An Introduction to Quantum Field Theory" by Peskin and Schroder.
  • Review the properties of annihilation and creation operators in quantum field theory.
  • Practice applying the commutation relation [A,BC] in various operator contexts.
  • Explore advanced topics in quantum field theory, such as perturbation theory and Feynman diagrams.
USEFUL FOR

Students and researchers in quantum field theory, physicists working with operator algebra, and anyone seeking to deepen their understanding of Wick's Theorem and its applications in particle physics.

jameson2
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I'm having a bit of trouble working through the induction proof they give in the book.
The step I don't understand is: (page 90 in the book, halfway down)
N(\phi_2...\phi_m)\phi_1^+ + [\phi_1^+,N(\phi_2...\phi_m)] = N(\phi_1^+\phi_2...\phi_m) + N([\phi_1^+,\phi_2^-]\phi_3...\phi_m + \phi_2[\phi_1^+,\phi_3^-]\phi_4...\phi_m + ...)

I've gone through the m=2 case in the book, and I did m=3 myself. But I just can't see how they get between the two lines above, even though I've convinced myself it should work.

If someone could explain it's be great, thanks.
 
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First of all, automatically N(\phi_2...\phi_m)\phi_1^{+}= N(\phi_1^{+}\phi_2...\phi_m) since \phi_1^{+} is purely made up of annihilation operators.
Second, you need to prove [\phi_1^{+}, N(\phi_2...\phi_m)]=N([\phi_1^{+},(\phi_2...\phi_m)]). To prove this you need induction again and the relation [A,BC]=[A,B]C+B[A,C]. After these you just commute the \phi_1^{+} through the string of operators \phi_2...\phi_m then you should get it.
 

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