Will a Box Slide on a Truck During a Sharp Turn?

Click For Summary
SUMMARY

The discussion centers on the dynamics of a 10 kg box on a truck making a left turn with a radius of 15 m at a speed of 12 m/s. The static friction coefficient is 0.45, and the kinetic friction coefficient is 0.20. It is established that the box does slide because the required centripetal force of 96 N exceeds the maximum static friction force of 44.1 N. The centripetal acceleration is calculated at 9.6 m/s², and further clarification is sought on determining the acceleration of the box when it slides.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of centripetal force and acceleration
  • Familiarity with static and kinetic friction coefficients
  • Ability to draw and interpret free-body diagrams
NEXT STEPS
  • Calculate the acceleration of the box using the formula for kinetic friction.
  • Explore the relationship between friction coefficients and sliding motion.
  • Investigate the effects of varying truck speeds on box stability.
  • Learn about the implications of different surface materials on friction.
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the principles of motion and friction in dynamic systems.

alotaattitude32
Here is the questions:
A box of mass m= 10 kg is sitting on the floor of a truck as the truck rounds a curve to the left of radius 15 m at 12 m/s. There is friction between the box and the floor of the truck with mus= .45 and muk = .20.

1. Does the box slide?
2. If the box slides, in what direction and with what acceleration?
3. If the box doesn't slide, what would the coefficient of static friction be in order for it to slide?
 
Physics news on Phys.org
alotaattitude32 said:
Here is the questions:
A box of mass m= 10 kg is sitting on the floor of a truck as the truck rounds a curve to the left of radius 15 m at 12 m/s. There is friction between the box and the floor of the truck with mus= .45 and muk = .20.

1. Does the box slide?
2. If the box slides, in what direction and with what acceleration?
3. If the box doesn't slide, what would the coefficient of static friction be in order for it to slide?
You will have to show us what you have done first. What are the forces on the box?

AM
 
So far i have drawn a free-body diagram with the normal force upward, and the centripetal, static friction, and kinetic friction forces drawn to the right. The force of gravity is of course pointing downward. I have calculated the Static force as being 44.1 N, the kinetic force as being 19.6 N, and the centripetal force as 96 N. I concluded that the box does slide because the centripetal force is greater than the frictional force. For centripetal acceleration i got 9.6 m/s^2. However, i was just confused as to how to calculate the acceleration when the box slides. Please help.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
14K
  • · Replies 15 ·
Replies
15
Views
4K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
2K