Sure, but if ##\psi_a(x, t)## is a solution, then your ##\psi(x, t)## will be equal to my ##\psi_a(x, t)##. So in that case, we can say that the wave function collapsed to ##\psi_a(x, t)## for
any ##t##, so the actual time of collapse ##t_0## is irrelevant and hence unphysical. We can even interpret it as if the collapse happened before the measurement, as in the delayed choice experiments. That's why one cannot associate with a collapse a definite time of collapse, which is related to the fact that collapse cannot be used for instantaneous communication.
If, on the other hand, ##\psi_a(x, t)## were not a solution, then we could determine a definite time of collapse and associated nonlinearity could be used for instantaneous communication.
One way of understanding it is this. Formally, a collapse is always nonlinear. But if there is no way to determine the time of collapse, then the time of nonlinearity is unphysical so for practical purposes one may interpret collapse as mere information update not corresponding to any actual nonlinear event. By contrast, if there is a way to determine the time of collapse, then the collapse is an actual physical event with measurable consequences, including instantaneous communication. If the Schrödinger equation is nonlinear, then the additional nonlinearity induced by collapse becomes physical and cannot longer be interpreted as mere information update.
For as related discussion see also
https://www.physicsforums.com/threa...-for-the-probabilistic-interpretation.991365/