colorSpace said:
It sounds like you are not distinguishing two very different things:
1. The state of superposition that the universe will be in from around the entangled particle. This is mind-boggling but "just" a huge state of superposition.
2. The "problem of label proliferation", which means that huge amounts of additional information about the past states needs to be carried along in addition to the superposition, in order to later-on enable the "pairing-up". As the text says, here "quantum field theory provides no explanation". If you think there is no "particular problem" here, then I submit you haven't recognized the problem yet.
That is because your 1. and 2. are exactly the same thing !
The "labels" we are talking about here, is the "term number" in the superposition!
Look at this:
imagine a universe with 3 particles in it. In "quantum speak", we take it that the first two particles are entangled, and the 3rd one is in a product state:
(|u1>|v1> + |u2>|v2>) |w0>
In "label talk", we have "two labels" here: one for the first term, and one for the second:
u1 gets "label A" together with v1.
u2 gets "label B" together with v2.
w0 doesn't have a label yet (in a product state).
Now, whatever will evolve out of the term |u1>|v1> will carry label A with it. Same for |u2>|v2> (label B).
Imagine now that the third particle interacts with, say, the first one:
w0 will now entangle with the u-states:
|u1>|v1>|w1> + |u2>|v2>|w2>
w now "inherits" the labels from u, that is to say, w1 inherits label A, and w2 inherits label B (from u1 resp. u2). In algebra, we simply had that |u1>|w0> evolved into |u1>|w1> and that |u2>|w0> evolved into |u2>|w2>, but because we're trying not to talk about wavefunctions, we have to do the algebra with "labels".
Label A means: gets into the first term, and label B means: gets into the second term.
Ok. Now let us consider a more complicated system:
|keyboardAlice0>|brainAlice0>|computerAlice0> (|u+>|v+> - |u->|v->) |thunderbird_bob0>|brainbob0>
There are two terms here, given by the entanglement of u and v, so we have two labels: A and B.
u+ and v+ have label A, u- and v- have label B.
Suppose that Alice does a measurement on u, but under a different angle. We have:
|u+> = x |uu+> + y |uu->
|u-> = -y |uu+> + x |uu-> with x and y the cos and sin of the angle of alice's analyser.
We rewrite this, using labels:
|keyboardAlice0>|brainAlice0>|computerAlice0> ((x |uu+A> + y |uu-A>)|v+A> - (-y |uu+B> + x |uu-B> )|v-B>) |thunderbird_bob0>|brainbob0>
Now, Alice's brain interacts with the measurement device (which interacts with the uu+ and uu- states). However, because this interaction is again a "product state which entangles", we need to introduce new labels (because there are new terms in the wavefunction): C,D,E and F:
|keyboardAlice0>|computerAlice0> ((x |uu+AC>|brainalice+AC> + y |uu-AD>|brainalice-AD>)|v+A> - (-y |uu+BE>|brainalice+BE> + x |uu-BF>|brainalice-BF> )|v-B>) |thunderbird_bob0>|brainbob0>
Note that there is some double usage (C and D include "A" and E and F include "B"). We could do better if we wanted but it doesn't matter.
The brain of alice states inherit now the labels A,B,...F. Note that this is of not much meaning in the wavefunction, as we know of course in which terms they are. But if you do not want to write an algebraic wavefunction, then you can write the "term number" with these labels. AC is the first term, AD is the second one, BE is the third one and BF is the fourth one.
Now, let's say that Bob does his measurement (along the original z axis). we now have:
|keyboardAlice0>|computerAlice0> ((x |uu+AC>|brainalice+AC> + y |uu-AD>|brainalice-AD>)|v+A>|brainbob+A> - (-y |uu+BE>|brainalice+BE> + x |uu-BF>|brainalice-BF> )|v-B>|brainbob-B>) |thunderbird_bob0>
At this moment, bob's brain inherits also the two labels A and B, from the v-states. Note that algebraically, A and B simply mean: first term and second term (from Bob's PoV).
Right, now Alice is going to send an email to bob with her results. First her keyboard gets hits from her fingers:
|computerAlice0> ((x |uu+AC>|brainalice+AC>|keyboardAlice+AC> + y |uu-AD>|brainalice-AD>|keyboardAlice-AD>)|v+A>|brainbob+A> - (-y |uu+BE>|brainalice+BE>|keyboardAlice+BE> + x |uu-BF>|brainalice-BF> |keyboardAlice-BF>)|v-B>|brainbob-B>) |thunderbird_bob0>
It gets its label of course from Alice's brain state.
Same for the computer:
((x |uu+AC>|brainalice+AC>|keyboardAlice+AC>|computerAlice+AC> + y |uu-AD>|brainalice-AD>|keyboardAlice-AD>|computerAlice-AD>)|v+A>|brainbob+A> - (-y |uu+BE>|brainalice+BE>|keyboardAlice+BE>|computerAlice+BE> + x |uu-BF>|brainalice-BF> |keyboardAlice-BF>|computerAlice-BF>)|v-B>|brainbob-B>) |thunderbird_bob0>
After sending the e-mail to Bob's email client (thunderbird), this e-mail agent gets also his label from this:
((x |uu+AC>|brainalice+AC>|keyboardAlice+AC>|computerAlice+AC>|thunderbird_bob+AC> + y |uu-AD>|brainalice-AD>|keyboardAlice-AD>|computerAlice-AD>|thunderbird_bob-AD>)|v+A>|brainbob+A> - (-y |uu+BE>|brainalice+BE>|keyboardAlice+BE>|computerAlice+BE>|thunderbird_bob+BE> + x |uu-BF>|brainalice-BF> |keyboardAlice-BF>|computerAlice-BF>|thunderbird_bob-BF>)|v-B>|brainbob-B>) Again, I want to stress that the labels do nothing else but to number the terms in the wavefunction! If you have the labels, you can reconstruct the wavefunction, and if you have the wavefunction, you can find the labels.
Right, now comes the crux: bob's going to read his e-mail:x |uu+AC>|brainalice+AC>|keyboardAlice+AC>|computerAlice+AC>|thunderbird_bob+AC> |v+AC>|brainbob++AC>
+ y |uu-AD>|brainalice-AD>|keyboardAlice-AD>|computerAlice-AD>|thunderbird_bob-AD> |v+AD>|brainbob+-AD> + y |uu+BE>|brainalice+BE>|keyboardAlice+BE>|computerAlice+BE>|thunderbird_bob+BE> |v-BE>|brainbob-+BE> - x |uu-BF>|brainalice-BF> |keyboardAlice-BF>|computerAlice-BF>|thunderbird_bob-BF>|v-BF>|brainbob--BF>Though the interaction with his e-mail, bob's brain interacts with the result of Alice, and learns about it (second sign + or - on the ket). It also inherits the labels.
We see that Bob has now 4 brainstates (++,+-,-+ and --) which correspond to 4 terms in the wavefunction, and to 4 labels (AC, AD, BE and BF) which have labelled these 4 terms.
So we see that the "labels" do nothing else but indicate the terms in the wavefunction. So it is EXACTLY the information of the superposition which is locked in these labels. We re-discover again the superposition principle, and the size of hilbertspace...EDIT: I will add something. In "bob's lifepath" he will first "split" over labels A and B (two "worlds") and later on, when he learns things from Alice, split again (in AC, AD, BE or BF).
So the "label proliferation" is nothing else but the consistent history of a particular Bob state in MWI. The number of labels corresponds to the number of histories. And these are nothing else but the different decohered terms in the "wavefunction of the universe".
So you can say that the "information to be carried by a state" is "the world in which it was, with its history". "know your world", as they say...
No, the situation cannot occur, and that is the problem. When an observer receives information from two of the measurements A and B at the midpoint AB, this will require pairing-up A states and B states, yet the possibilities of pairing-up depend on not-yet available information from C (the GHZ measurement angle at C, in the GHZ scenario). That means, or seems to, that some of the superpositions that develop at Ab will later-on become impossible. At least that is the challenge to be answered in this scenario.
I don't understand this. Could you work out the wavefunction symbolically (as I did with Alice and Bob) ?