What is the maximum speed the car can have to avoid hitting the barrier?

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SUMMARY

The discussion focuses on determining the maximum speed a car can travel without hitting a barrier located 40.0 meters ahead. The driver initially travels at 90 km/h (25 m/s) and takes 0.75 seconds to apply the brakes, with an average deceleration of -10.0 m/s². It is established that the car will hit the barrier if it continues at this speed, as it requires 50 meters to stop completely. To find the maximum speed that would allow the car to stop just before the barrier, the equation v2² = v1² + 2a(delta(d)) is utilized, where v2 is 0 m/s, and the distance to the barrier is 40.0 m.

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adamlazz
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Hi there, I am a grade 11 student, learning physics.

Homework Statement



A driver of a car going 90km/h suddenly sees the lights of a barrier 40.0 m ahead. It takes the driver 0.75s before he applies the brakes and the average accelleration during braking is -10.0m/s2.
a) Determine whether or not the car hits tha barrier.
b) What is the maximim speed at which the car could be moving and not hit the barrier at 40.0 m ahead? Assume the accelleration does not change.

a) Treat toward the barrier as positive.
v2=0m/s delta(t)= 40
v1=25m/s
a=-10m/s2

I am not quite sure how to do b)


Homework Equations



v2^2 = v1^2 + 2a(delta(d)) <---- a)

The Attempt at a Solution



I have already determined that it would take the car 50 m to come to a complete stop, so it would hit the barrier.

I am having trouble with b)


thanks in advance.
 
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I could be wrong but you just need to use the same formula again:

v2^2 = v1^2 + 2a(delta(d)) <---- a)

You know d, v2 is 0, and your given acceleration from before

There is only one unknown left, V1.
 
If you assume the car will stop just before it hits the barrier, you now have a new piece of information you can use in your equations to work out the new v1.
 

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