Will the Command in the Algorithm Execute if A[1]==5?

[evinda]

Hello! (Wave)

Consider that we have an algorithm of the form:

Algorithm(A[1...n], low, high){
    mid=low+floor((high-low)/2);
    if (A[1]==5) { command }
    commands
    Algorithm(A,mid+1,high)
}

When we call

Algorithm(A,mid+1,high)

will the command of the if statement (if A[1]==5) be executed? (Thinking)

 

[alyafey22]

Hello! (Wave)

Consider that we have an algorithm of the form:

Algorithm(A[1...n], low, high){
    mid=low+floor((high-low)/2);
    if (A[1]==5) { command }
    commands
    Algorithm(A,mid+1,high)
}

When we call

Algorithm(A,mid+1,high)

will the command of the if statement (if A[1]==5) be executed? (Thinking)

It will be executed but the logical result of the if statement depends on the array it self (Is the first value equal to 5?) .

Am I misunderstanding your question ?

 

[evinda]

It will be executed but the logical result of the if statement depends on the array it self (Is the first value equal to 4 ?) .

Am I misunderstanding your question ?

If we call the function

 Algorithm(A,mid+1,high)

will the first element of the subarray be equal to $A[1]$ or to $A[mid+1]$?

So, will the command of the if-statement be executed or not? (Thinking)

 

[alyafey22]

If we call the function

 Algorithm(A,mid+1,high)

will the first element of the subarray be equal to $A[1]$ or to $A[mid+1]$?

So, will the command of the if-statement be executed or not? (Thinking)

Let the following 
A = {4 , 5 , 6 , 2 , 3 , 1} 
If we call Alogrithm(A , 1 , 6);
mid = 3;
A[1] = 4 

in the second call 

Alogrithm (A , 4 , 6)
mid = 5
A[1] = 4 // no change in the value of the array.

 

[evinda]

Let the following 
A = {4 , 5 , 6 , 2 , 3 , 1} 
If we call Alogrithm(A , 1 , 6);
mid = 3;
A[1] = 4 

in the second call 

Alogrithm (A , 4 , 6)
mid = 5
A[1] = 4 // no change in the value of the array.

So, the value of A[1] will not change, right? (Thinking)

Thanks a lot! (Smile)

 

[alyafey22]

So, the value of A[1] will not change, right? (Thinking)

Thanks a lot! (Smile)

Yes , because we are not changing the value we are changing the indices.