WiMAX Transmitter: Can 1 EXAbit/sec be Transmitted?

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WiMAX networks can provide a 30 Mbit connection to users up to 50 km away, but the calculation for achieving 1 EXAbit/sec is flawed. The inverse power law is mentioned, but the correct approach involves using the Friis formula to determine received signal power. This formula helps assess whether the signal can compete with system noise. Understanding these principles is crucial for evaluating WiMAX transmission capabilities. Accurate calculations are essential for realistic expectations of data transfer rates.
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I was reading about WiMAX networks and how they can provide a 30mbit connection to a user 50km away!

Now, I don't have a great understanding of data transfer but I assume inverse power law applies??

Pf = Pi / 4*pi*r^2

At 50km

Pf = Pi / 10^10 * pi

For Pf = 30mbit/sec = 30*10^6
Pi must equal:

30*10^6 * 10^10 * pi = 10^18 bits/sec = 1 EXAbit/sec

Really?! Can they transmit an EXAbit of data per second? How the hell do these things work?!
 
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leonmate said:
I was reading about WiMAX networks and how they can provide a 30mbit connection to a user 50km away!

Now, I don't have a great understanding of data transfer but I assume inverse power law applies??

Pf = Pi / 4*pi*r^2

At 50km

Pf = Pi / 10^10 * pi

For Pf = 30mbit/sec = 30*10^6
Pi must equal:

30*10^6 * 10^10 * pi = 10^18 bits/sec = 1 EXAbit/sec

Really?! Can they transmit an EXAbit of data per second? How the hell do these things work?!
The calculation is incorrect. You need to look up the Friis formula on the Internet as a starting point. This will give the received signal power, and then you need to work out if it will compete with the noise of the system.
 
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