Win Free Stuff at Work: Game Theory Strategies

Click For Summary

Discussion Overview

The discussion revolves around a game played in an office setting where participants guess the lowest unique positive integer in order to win prizes. The conversation explores strategies for selecting numbers based on the number of participants and the implications of game theory, particularly Nash equilibrium, on these strategies.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests that for one person, the best guess is 1, and for two people, 1 remains the best guess, but expresses uncertainty for three participants.
  • Another participant references external sources and proposes that an exponential distribution of probabilities might be optimal, noting that the best strategy cannot be a single number since everyone will aim for the same strategy.
  • One participant posits that the best number should be between 1 and (n/2+1) to maximize chances of uniqueness, but questions what happens if no unique guesses are made.
  • A later reply challenges the initial observation about the best number range, providing a specific example with a three-player game and different probability distributions, suggesting that the initial assumption may not hold true in standard gameplay.

Areas of Agreement / Disagreement

Participants express differing views on the optimal guessing strategy, with some supporting the idea of guessing within a specific range while others contest this notion based on probability distributions. The discussion remains unresolved regarding the best approach to take in the game.

Contextual Notes

The discussion includes assumptions about participant behavior and the nature of the game, which may not be universally applicable. There are also unresolved mathematical considerations regarding the impact of alliances and unique guesses.

Diffy
Messages
441
Reaction score
0
In the office I work, there is a popular game when someone wants to give something away. When a person has something to give away, they send out an email to 'n' people. The email directs the recipients to try and guess the lowest positive integer they can that is unique amoung all the responses. So the email would look like:

"You need to send a guess which is a positive integer (1, 2, 3…) The person who guesses the lowest unique number wins."

I was wondering, based on the number of people 'n' is there a best guess?

For 1 person, 1 is the best guess for obvious reasons.
For 2 people I think 1 is still the best guess. If the other person also guess is 1, its a tie, if not you win.

For 3 people I am not sure.

I am looking for people who are smart then me to help me devise a strategy to win baseball tickets, software licenses, old hardware, booze, and other misc giveaways at my work.
 
Physics news on Phys.org
I tried googling:
http://www.tinbergen.nl/discussionpapers/08049.pdf
http://mathoverflow.net/questions/27004/lowest-unique-bid

Let me know what it say :)
I guess some exponential distribution of probabilities is best. Obviously the best strategy cannot be just one number, as everyone wants to use the best strategy, however if that was the best, then surely someone would want to depart.
The Nash equilibrium means the best strategy can be adopted by everyone and no-one would like to depart if everyone uses it.
 
Last edited by a moderator:
Initial observation: the best number has to be between 1 and (n/2+1). If any of those numbers are untaken by everyone else, then your best choice is to take that number or to guess lower. If all those numbers are taken, at least one of them has only one person guessing it and you're screwed.

I noticed that the mathoverflow post and one of the papers cited there don't take this into account it seems (the paper restricts picks to be between 1 and n). It might be that picking numbers larger than n/2+1 is a good idea to minimize your chance of overlapping with someone else, so it brings up a question: If nobody has a unique guess what happens?

Also observe that if you can get half the people in the office into an alliance, you can guarantee your alliance wins all the prizes by just inputting those numbers. How you then divvy up the winnings is up to you of course (you can play this game again amongst yourselves. And then see how far down the rabbit hole you can go with it. Note: This is unlikely to make you many friends, but if everyone is sworn to the proper level of secrecy nobody will know that they're still one of the chumps).
 
Office_Shredder said:
Initial observation: the best number has to be between 1 and (n/2+1).
While intuitively appealing, it is not true for the standard game.

For example, consider a three-player game where you know your opponents will choose according to the distribution:
  1. 1/2
  2. 1/4
  3. 1/4
In the standard game, your odds of winning for each choice of number is
  1. 4/16
  2. 5/16
  3. 5/16
  4. 6/16
In the variant of the opening post, the odds are
  1. 1/3
  2. 1/3
  3. 1/3
  4. 3/8
 
Last edited:

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 11 ·
Replies
11
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
10K
Replies
13
Views
3K
Replies
11
Views
6K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 12 ·
Replies
12
Views
4K
  • Poll Poll
  • · Replies 10 ·
Replies
10
Views
7K