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With what speed does the object get nearer to the reflection

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  1. May 19, 2016 #1
    1. The problem statement, all variables and given/known data
    An object gets closer to the plain mirror with a speed v. With which speed does it get closer to the reflection?

    2. Relevant equations
    l=v*t

    3. The attempt at a solution
    As l (length of road) is twice as big l2=2l1, but the time is equal t1=t2, then velocity should be two times bigger. Am I right?
     
  2. jcsd
  3. May 19, 2016 #2

    CWatters

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    Your answer is correct but I'm not sure I understand your reasoning.
     
  4. May 19, 2016 #3
    Could you give me a hint about the correct one?
     
  5. May 19, 2016 #4

    haruspex

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    You need to explain how you are defining t1 and t2. These are the times taken to do what? (I believe your reasoning is fine if you fill that in appropriately.)
     
  6. May 19, 2016 #5
    t1 is the time taken to meet the mirror, t2 i the time taken to meet the reflection. As the mirror and reflection are met in the same time t1=t2
     
  7. May 19, 2016 #6

    haruspex

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    With that preamble, your answer looks good to me.
     
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