Placing object between 2 spherical mirrors

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Homework Help Overview

The problem involves a concave mirror and a convex mirror facing each other, with an object placed between them. The task is to determine the distance of the image produced by the convex mirror after light reflects off both mirrors.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the image distance produced by the concave mirror and its implications for the convex mirror. There are questions about the nature of the image (real or virtual) and its position relative to the convex mirror.

Discussion Status

Some participants have provided calculations and are exploring the implications of the image being virtual. There is an ongoing dialogue about whether the object distance for the convex mirror should be treated as negative based on the image's position.

Contextual Notes

Participants are considering the effects of the mirrors' focal lengths and the distance between the mirrors, as well as the conventions for sign in optics. There is a focus on understanding the setup and the resulting image characteristics.

ilovejava
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Homework Statement


A concave mirror (f1 = 13.6 cm) and a convex mirror (f2 = −7.00 cm) are facing each other and are separated by a distance of 35.8 cm. An object is placed between the mirrors and is 17.9 cm from each mirror. Consider the light from the object that reflects first from the concave mirror and then from the convex mirror. What is the distance of the image (di2) produced by the convex mirror?

Homework Equations


1/do + 1/i = 1/f

The Attempt at a Solution


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The image created by the concave mirror will act as the object for the convex mirror. Plugging in the values for do and f for the concave mirror I got di = 56.6cm . Therefore, the do for the convex mirror will be 56.6-35.8 (distance mirrors are separated by) = 20.8 . Lastly, I just plugged this value and the focal length of the convex mirror into 1/do + 1/i = 1/f and got -5.24cm as di2
 
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Does the image at 56.6 cm appear in front of or behind of the convex mirror? You should draw a ray diagram.
 
kuruman said:
Does the image at 56.6 cm appear in front of or behind of the convex mirror? You should draw a ray diagram.
I drew one out and it appears that the image forms behind the convex mirror. So this would be a virtual object does that mean I should have made 20.8 negative?
 
ilovejava said:
I drew one out and it appears that the image forms behind the convex mirror. So this would be a virtual object does that mean I should have made 20.8 negative?
Yes.
 

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