With which sample(s) of halide does sulphuric acid act as an oxidising agent?

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SUMMARY

Concentrated sulphuric acid acts as an oxidizing agent specifically with sodium bromide and sodium iodide, leading to the formation of bromine (Br2) and iodine (I2) respectively. The correct answer to the posed question is option C: sodium bromide and sodium iodide. The reactions can be represented as NaX + H2SO4 → NaHSO4 + HX, where X represents the halide ions. Understanding the reactivity of halides with concentrated sulphuric acid is essential for accurately predicting the outcomes of these reactions.

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Concentrated sulphuric acid is added to separate solid samples of sodium chloride, sodium
bromide or sodium iodide.
With which sample(s) does sulphuric acid act as an oxidising agent?
A sodium chloride only
B sodium chloride and sodium bromide
C sodium bromide and sodium iodide
D sodium iodide only

The answer is C. But what is the explanation? How do I approach questions like these, because I have no clue how to find the answer. I tried writing an equation for the 3 reaction, and they are all the same!
NaX + H2SO4 --> NaHSO4 + HX ( You can also use the Na2SO4 reaction) So what thread do I follow to crack this?
 
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It only oxidises Br- and I- to Br2 and I2 so C.) sodium bromide and sodium iodide should be the correct option
 
mutineer123 said:
Concentrated sulphuric acid is added to separate solid samples of sodium chloride, sodium
bromide or sodium iodide.
With which sample(s) does sulphuric acid act as an oxidising agent?
A sodium chloride only
B sodium chloride and sodium bromide
C sodium bromide and sodium iodide
D sodium iodide only

The answer is C. But what is the explanation? How do I approach questions like these, because I have no clue how to find the answer. I tried writing an equation for the 3 reaction, and they are all the same!
NaX + H2SO4 --> NaHSO4 + HX ( You can also use the Na2SO4 reaction) So what thread do I follow to crack this?

http://www.chemguide.co.uk/inorganic/group7/halideions.html
 

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