Hello people...could u help me pls...coz i am rly stuck in these thing like calculations...i know all right answers but i am not too sure how to get them...please if somebody of us has a few minutes could u help me with that? Thank you very much. 1., When 0.25 g of sodium metal was added to 200 cm3 ( an excess ) of water , the following reaction occured. Na(s) + H20 (l) --> NaOH ( aq ) + 1/2 H2 (g ) (i) calculate the number of moles of sodium taking part in the reaction. Na = 23 g mol-1 0.25g / 23 g mol-1 = 0.011 mole (ii) calculate the molarity of the sodium hydroxide solution which was formed. (iii) calculate the volume of hydrogen gas produced at r.t.p. (298 K and 100 kPa ). Assume that hydrogen is insoluble in water under these conditions. In another experiment 25.0 cm3 of 0.183 M sodium hydroxide were neutralised by 13.7 cm3 of sulphuric acid according to the following equation. 2NaOH (aq) + H2SO4 (aq) --> Na2SO4 (aq) + 2H2O ( l ) Calculate the molarity of the sulphuric acid.