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Work and energy with normal force

  1. Nov 10, 2008 #1
    1. The problem statement, all variables and given/known data
    Starting from rest, a 5.85 kg block slides 2.07m down a rough 26.4degree incline. The coefficient of kinetic friction between the block and the incline is 0.427. The acceleration of gravity is 9.8m/s^2. Find the work done by the normal force. Answer in units of Joules.

    Here's my FBD.
    [​IMG]

    I know the formula for work is Fcos(theta)d. But I don't know how to find the angle for the normal force...
    If someone could help out, I would really appreciate it.
     
  2. jcsd
  3. Nov 10, 2008 #2

    mgb_phys

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    The normal force acts at right angles to the slope.
    You 26.4 is in the wrong place - a slope angle of 26.4 means the angle between the slope and horizontal.
     
  4. Nov 10, 2008 #3
    yes, but if you draw some parallel lines, the 26.4 degrees of the slope angle is also equivalent to that angle up there. oh but i see what you said about the normal being perpendicular...wouldnt that mean work is zero then?
     
  5. Nov 10, 2008 #4

    LowlyPion

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    Yes you are right that forces in the direction of motion are the ones that do work, but in the case of the Normal force there is a resulting force along the direction of motion as determined by the Normal force * the Coefficient of Friction.
     
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