Work and Force on a block of mass

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SUMMARY

The discussion centers on calculating the work done on a 5.0 kg block pushed 3.0 meters up a vertical wall at a constant velocity, with a force applied at a 30.0-degree angle and a coefficient of kinetic friction of 0.30. The work done by the applied force was calculated as 38.23 J using the equation W = Fd cos(θ). The work done by gravity was computed using W = mgh, while the normal force was determined as 42.48 N. The importance of drawing a free body diagram to identify forces acting on the block was emphasized for accurate calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with work-energy principles
  • Knowledge of free body diagrams
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Study the concept of free body diagrams in physics
  • Learn about the work-energy theorem and its applications
  • Explore the effects of friction on motion, particularly in inclined planes
  • Investigate the relationship between normal force and frictional force
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work and force calculations in real-world applications.

chamonix
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Homework Statement


A 5.0 kg block is pushed 3.0 meters at a constant velocity up a vertical wall by a constant florce applied at an angle of 30.0 degrees witht the horizontal. If the coefficient of kinetic friction between the block and the wall is 0.30, determine the following:
a) the work done by the force on the block
b) the work done by gravity on the block
c) the magnitude of the normal force between the block and the wall


Homework Equations


W=Fdcosø
W=mgh
Fn=mgcosø


The Attempt at a Solution


W=Fdcosø
W=mu*mgdcosø
W=.3*5*9.81*3*cos30
W=38.23J

w=mgh
w=5*9.81*3

fn=mg
fn=5*9.81*cos30
fn=42.48

I have a feeling that this is wrong. Any help would be most appreciated. Thanks.
 
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chamonix said:

Homework Statement


A 5.0 kg block is pushed 3.0 meters at a constant velocity up a vertical wall by a constant florce applied at an angle of 30.0 degrees witht the horizontal. If the coefficient of kinetic friction between the block and the wall is 0.30, determine the following:
a) the work done by the force on the block
b) the work done by gravity on the block
c) the magnitude of the normal force between the block and the wall


Homework Equations


W=Fdcosø
W=mgh
Fn=mgcosø


The Attempt at a Solution


W=Fdcosø
W=mu*mgdcosø
W=.3*5*9.81*3*cos30
W=38.23J

w=mgh
w=5*9.81*3

fn=mg
fn=5*9.81*cos30
fn=42.48

I have a feeling that this is wrong. Any help would be most appreciated. Thanks.
You should first draw a free body diagram of the block, and identify all the forces acting on the block. In particular, the Normal force is the force the wall exerts on the block, perpendicular to it. In this problem, the Normal force has nothing to do with the block's weight. Then use Newton 1 before attempting a solution to the work done by the force.
 
Thank you. I will try this.
So, would my equations for the problems be correct?
 
Last edited:

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