Work & Friction: Solve for Force, Work, & Speed

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SUMMARY

The discussion focuses on calculating work and friction forces in a physics problem involving a 16.1 kg block being dragged over a rough surface. The constant force applied is 118 N at an angle of 25 degrees, with a coefficient of kinetic friction of 0.228. The work done by the applied force is calculated to be 8405.82346 J. The participants emphasize the importance of understanding the relationship between work, friction, and speed to determine the final velocity of the block.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of work-energy theorem
  • Familiarity with friction force calculations
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Calculate the work done by the force of friction using the formula: Work = Friction Force x Distance
  • Learn how to apply the work-energy theorem to find final speed from net work done
  • Explore the concept of kinetic friction and its impact on motion
  • Investigate the relationship between force, mass, and acceleration in practical scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces, work, and motion in real-world applications.

lostinthespiral
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I am having real trouble understanding friction force. Work I understand. I just don't know how to put them together. Some help would be highly appreciated.

A 16.1 kg block is dragged over a rough, horizontal surface by a constant force of 118 N acting at an angle of 25 degrees above the horizontal. The block is displaced 78.6 m, and the coeficient of kinetic friction is 0.228. The acceleration of gravity is 9.8 m/s2.

a.) Find the work done by the 118 N force. Answer in units of J. - I've already found this to be 8405.82346 J

b.) Find the work done by the force of friction. Answer in units of J.

c.) If the block was originally at rest, determine its final speed. Answer in units of m/s2.
 
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Net work done on object = (horizontal component of 118 - frictional force) * distance

Net work done on object = change in kinetic energy (work-energy theorem)
 
lostinthespiral said:
I am having real trouble understanding friction force. Work I understand. I just don't know how to put them together. Some help would be highly appreciated.

A 16.1 kg block is dragged over a rough, horizontal surface by a constant force of 118 N acting at an angle of 25 degrees above the horizontal. The block is displaced 78.6 m, and the coeficient of kinetic friction is 0.228. The acceleration of gravity is 9.8 m/s2.

a.) Find the work done by the force of friction. Answer in units of J. - I've already found this to be 8405.82346 J

b.) Find the work done by the force of friction. Answer in units of J.

c.) If the block was originally at rest, determine its final speed. Answer in units of m/s2.


Please,review both the text (the first question and the second are identical),and the result to your first calculation.
For the third,compute the time in which the body moves along those 78,6 m and from there,u can find the velocity.
 
Alright. Fixed.
 

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