Work and heat transfer in internal combustion engine

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SUMMARY

The discussion centers on calculating the power absorbed during the compression stroke of a two-cylinder internal combustion engine, where the compression law is defined as PV1.2 = const. The initial pressure is 101.325 kPa, and the volume is reduced to 1/5 of its original size. The correct power output calculated is 17.95 kW at an engine speed of 500 compression strokes per minute. Participants debated the validity of the compression exponent, with some suggesting it should be 1.4 instead of 1.2, but the consensus confirmed the use of 1.2 for this scenario.

PREREQUISITES
  • Understanding of thermodynamics, specifically the adiabatic process
  • Familiarity with internal combustion engine mechanics
  • Knowledge of the ideal gas law and its applications
  • Ability to perform calculations involving pressure, volume, and power
NEXT STEPS
  • Study the derivation of the adiabatic process equations in thermodynamics
  • Learn about the implications of different compression ratios in internal combustion engines
  • Research the effects of engine speed on power output and efficiency
  • Explore the differences between isothermal and adiabatic compression processes
USEFUL FOR

Engineers, mechanical engineering students, and automotive professionals involved in the design and analysis of internal combustion engines will benefit from this discussion.

Suman_babai
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Homework Statement

: [/B]At the beginning of the compression stroke of a two-cylinder internal combustion engine the air is at a pressure of 101.325 kPa. Compression redeuces the volume to 1/5 of its original volume, and the law of compression is given by PV^1.2 = const. If the bore and stroke of each cylinder is 0.15 m and 0.25 m , respectively, determine the power absorbed in kW by compression strokes when the engine speed is such that each cylinder undergoes 500 compression strokes per minute.

The answer is given as : 17.95 kW

2. Homework Equations :
I hv written all formulas in the solution (attachment).

The Attempt at a Solution

:[/B] I hv attached the solution I hv done. Please rectify my mistake... where I am doing wrong..my ans is not matching with the given one.
 

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Suman_babai said:
given by PV^1.2 = const.
Are yo usure this is not pV^1.4 ?
 
Replusz said:
Are yo usure this is not pV^1.4 ?
that could be a printing mstake... thanks... this book is just full of calculation errors.
 
And if you calculate it with 1.4? do you get the right answer? (it is 1.4 because for adiabatic expressions pV^(1+2/f)=const. and f=5 for air. )
 
Replusz said:
And if you calculate it with 1.4? do you get the right answer? (it is 1.4 because for adiabatic expressions pV^(1+2/f)=const. and f=5 for air. )
no.. it is coming around 16.(something)... may be the question is wrong.. thanks anyway.
 
Suman_babai said:

Homework Statement

: [/B]At the beginning of the compression stroke of a two-cylinder internal combustion engine the air is at a pressure of 101.325 kPa. Compression redeuces the volume to 1/5 of its original volume, and the law of compression is given by PV^1.2 = const. If the bore and stroke of each cylinder is 0.15 m and 0.25 m , respectively, determine the power absorbed in kW by compression strokes when the engine speed is such that each cylinder undergoes 500 compression strokes per minute.

The answer is given as : 17.95 kW

2. Homework Equations : I hv written all formulas in the solution (attachment).

The Attempt at a Solution

:[/B] I hv attached the solution I hv done. Please rectify my mistake... where I am doing wrong..my ans is not matching with the given one.
Here is correct solution bro. V1-V2= Volume swept by piston.
Volume swept by piston not equal to v1, where you went wrong.
 

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