- #1
physics1234
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Find the work done by a gas when it is expanded from a volume of 1.0 L to 3.3 L at a constant pressure of 2.8 atm.
I converted the atm to Pascals by multiplying 2.8 x 101325 to get 283710.
Then I used the formula W=p(deltaV)
so 283710 x (3.3-1.0) = 652533
I don't understand why this is the wrong answer.
I converted the atm to Pascals by multiplying 2.8 x 101325 to get 283710.
Then I used the formula W=p(deltaV)
so 283710 x (3.3-1.0) = 652533
I don't understand why this is the wrong answer.