Work- constant pressure, changing volume

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SUMMARY

The work done by a gas during expansion from 1.0 L to 3.3 L at a constant pressure of 2.8 atm is calculated using the formula W = P(ΔV). The initial calculation incorrectly used Pascals instead of kilopascals, and the volume should be converted to cubic meters. The correct pressure conversion is 2.8 atm multiplied by 101.3 to yield 283.64 kPa, and the volume change should be expressed in cubic meters (0.0023 m³). The accurate work done is 652.53 Joules.

PREREQUISITES
  • Understanding of gas laws and thermodynamics
  • Familiarity with unit conversions (atm to kPa, L to m³)
  • Knowledge of the work formula in physics (W = PΔV)
  • Basic proficiency in handling pressure and volume measurements
NEXT STEPS
  • Learn about the Ideal Gas Law and its applications
  • Study unit conversion techniques for pressure and volume
  • Explore thermodynamic processes and their calculations
  • Investigate the implications of work done in different gas expansion scenarios
USEFUL FOR

Students in physics or engineering, professionals in thermodynamics, and anyone involved in calculations related to gas behavior and work done during expansion.

physics1234
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Find the work done by a gas when it is expanded from a volume of 1.0 L to 3.3 L at a constant pressure of 2.8 atm.

I converted the atm to Pascals by multiplying 2.8 x 101325 to get 283710.

Then I used the formula W=p(deltaV)

so 283710 x (3.3-1.0) = 652533

I don't understand why this is the wrong answer.
 
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Nevermind, I got it :-)

Thanks anyway!
 
hi brother
so as to your answer be at joule
you must convert the volume to cubic meter m3 , and to convert the pressure to kpa not pascal , by multiplying by 101.3 , try the new answer...

sorry my english is not so good
 

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