Work Done by a Constant Force (Q6 page 188 of Cutnell and Johnson)

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Homework Help Overview

The discussion revolves around calculating the work done by a constant force, specifically the tension in a rope pulling a toboggan over a distance of 35.0 m at an angle of 25.0° above the horizontal. Participants are examining the relationship between force, distance, and the angle in the context of work done in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for work, questioning the correct application of the equation W = (F cos Θ) s. There are inquiries about the meaning of variables and units, particularly regarding the use of distance in the context of force and work. Some participants express confusion over the inclusion of distance in calculations and the apparent discrepancies in answers.

Discussion Status

The discussion is ongoing, with participants attempting to clarify their understanding of the work formula and its components. Some have provided corrections to their earlier statements, while others are still grappling with the concepts and the implications of different interpretations of the formula.

Contextual Notes

There appears to be confusion regarding the correct distance to use in calculations, as well as the interpretation of the formula components. Participants are also addressing potential misunderstandings about the relationship between force, distance, and the angle in the context of work.

gcombina
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6.A person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 25.0° above the snow. The tension in the rope is 94.0 N.

a) How much work is done on the toboggan by the tension force? Ok, so W = (F cos Θ) s
= (94.0 cos 25°) 25 m
= WRONG ANSWER

I know the answer is 94.0 times distance but that would equal WORK right (fs)

why are they doing (94.0 N)(35.0 M) = Force?

**this is really frustrating , why are they including distance as force?
 
Last edited:
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So what does it say in terms of a "right" answer or solution?

Why does your solution have 94.0 twice?
 
gcombina said:
6.A person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 25.0° above the snow. The tension in the rope is 94.0 N.

a) How much work is done on the toboggan by the tension force? Ok, so W = (F cos Θ) s
= (94.0 cos 25°) 94.0 N
Hi gcombina. What does that "s" in your formula stand for? What units would it have?

Also, what are the units of that "W"?
 
this is the "right" answer

W = (94.0 N) (35.0 m) cos 25.0 = 2980 J
 
olivermsun said:
So what does it say in terms of a "right" answer or solution?

Why does your solution have 94.0 twice?


it was my mistake, i corrected it already.
 
NascentOxygen said:
Hi gcombina. What does that "s" in your formula stand for? What units would it have?

Also, what are the units of that "W"?
basically, this is the right answer => (94.0 N) (35.0 m) cos 25° =2980 J

this is formula (F cos θ)s I always use, but now they are using (Fs cos θ), where is this formula comes from?

I though W = (F cos θ)s and NOT (Fs cos θ)
 
Uhmmmm ... It is the same. Multiplication is commutative so it does not matter what order you multiply things in.
 
gcombina said:
basically, this is the right answer => (94.0 N) (35.0 m) cos 25° =2980 J

this is formula (F cos θ)s I always use, but now they are using (Fs cos θ), where is this formula comes from?

I though W = (F cos θ)s and NOT (Fs cos θ)
Do these give the same answer?
 
NascentOxygen said:
Do these give the same answer?

no, they don't give the same answer

Fs cos θ => (94.0 N) (35.0 m) cos 25° =2980 J

AND

F cos θ => (94.0 N) cos 25° = 85.19 J
 
  • #10
gcombina said:
F cos θ => (94.0 N) cos 25° = 85.19 J

Check your units. You wrote Joules but it is actually Newtons.

I think you meant "(F cos θ)s"? In which case, you do get the same answer.
 
  • #11
gcombina said:
Ok, so W = (F cos Θ) s
= (94.0 cos 25°) 25 m
The distance is 35m, not 25m.
 
  • #12
There is something very fundamental that you are misunderstanding, but I'm having difficulty identifying what.

gcombina said:
why are they doing (94.0 N)(35.0 M) = Force?

**this is really frustrating , why are they including distance as force?

They aren't. It's difficult to see why you might think they are.

F s cosθ = Force x distance x cosθ
 
  • #13
Starting from the beginning, step by step:

W = (F cos Θ) s

The distance is s = 35.0 m
The force in the direction that the distance is measured over is F cos Θ = (94.0 N)(cos 25°)

W = (F cos Θ) s = (94.0 N)(cos 25°)(35.0 m) = 2980 N m = 2980 J.
 

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