How Does the Angle of Force Application Affect Work Done on a Cart?

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Homework Help Overview

The problem involves a shopper pushing a cart in a supermarket, examining how the angle of force application affects the work done on the cart. The subject area includes concepts of work, force, and friction in the context of physics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the work done in two scenarios: one where the force is applied at an angle and another where it is applied horizontally. Questions arise regarding the calculation of work done and the implications of changing the angle of force application.

Discussion Status

Participants are exploring the implications of the angle of force application on the work done. Some guidance has been offered regarding the change in force when applied horizontally, and there is an acknowledgment of the original poster's confusion about the calculations involved.

Contextual Notes

There is a mention of the original poster's uncertainty about the calculations for work done and the implications of maintaining constant speed while changing the angle of force application. Additionally, there are references to potential unit discrepancies in the original poster's answers.

Zynoakib
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Homework Statement


A shopper in a supermarket pushes a cart with a
force of 35.0 N directed at an angle of 25.08 below
the horizontal. The force is just sufficient to balance
various friction forces, so the cart moves at constant
speed. (a) Find the work done by the shopper
on the cart as she moves down a 50.0-m-long aisle.
(b) The shopper goes down the next aisle, pushing horizontally
and maintaining the same speed as before.
If the friction force doesn’t change, would the shopper’s
applied force be larger, smaller, or the same?
(c) What about the work done on the cart by the
shopper?

I only don't understand (c)

Homework Equations


W = Fd

The Attempt at a Solution


The answer for (c) is "the same" (as the answer of (a) which is 1586N). I understand since the car travels the same distance, the work done by force should be the same as (a), but if I use W = Fd to calculate (c), it should be W = (35)(50) which is not the same as (a). So, why is that?

Thanks!
 
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For (c), the force done on the cart is not equal to 35 anymore. The speed of the cart is maintained, but not the force. Remember that the force is no longer applied at an angle.
 
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Likes   Reactions: Zynoakib and senan
What did you answer for b?
(Your answer to a has the wrong units.)
 
haruspex said:
What did you answer for b?
(Your answer to a has the wrong units.)

smaller

ecastro said:
For (c), the force done on the cart is not equal to 35 anymore. The speed of the cart is maintained, but not the force. Remember that the force is no longer applied at an angle.

Ok, I get it now. Thanks!
 

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