Work done by a moving conductor in a magnetic field

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SUMMARY

The discussion centers on calculating the force and work done by a moving conductor in a magnetic field. Using the formula F = BIL, a force of 0.1N is confirmed for a conductor of length 100mm carrying a current of 10A in a magnetic flux density of 0.1T. The work done, calculated using W = Fd, should yield 0.1J when the conductor is displaced by 100mm, contrary to an initial incorrect calculation of 0.01J. The confusion arose from misinterpreting the displacement in relation to the work done.

PREREQUISITES
  • Understanding of Lorentz force law (F = BIL)
  • Familiarity with the concept of magnetic flux density (B)
  • Knowledge of work-energy principle (W = Fd)
  • Basic principles of electromagnetism
NEXT STEPS
  • Review the derivation of the Lorentz force law in electromagnetism
  • Study the relationship between magnetic flux density and current-carrying conductors
  • Explore the work-energy theorem in the context of electromagnetic systems
  • Investigate practical applications of moving conductors in magnetic fields
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Physics students, electrical engineers, and educators seeking to deepen their understanding of electromagnetic forces and work done by conductors in magnetic fields.

chris19802
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Homework Statement



Show that there is a force of 0.1N on a conductor of length 100mm carrying a current of 10A at right angles to a flux density of 0.1T.

Show that 0.1J of work is done if the conductor is displaced by 100mm at right angles to its length.

Homework Equations



F=BIL
W=Fd

The Attempt at a Solution



I think this should be very straightforward, but the second bit confuses me. For the first bit I simply have:

F=BIL
F=0.1 x 0.1 x 10 = 0.1N

That's easy, but then for the second part concerning work I would imagine that:

W=Fd
W=0.1N x 0.1m = 0.01J

However the question says that the answer should be 0.1J of work. Is this a misprint or am I missing something really fundamental?

Thanks in advance.
 
Physics news on Phys.org
Yes, it's a misprint.
 
Thanks! Good to know.
 

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