What Is the Work Done by an External Force on a Transported Electron?

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Homework Help Overview

The problem involves calculating the work done by an external force on an electron being transported between two point charges, Q1 and Q2, with given values. The context is rooted in electrostatics and electric potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the electric potential at two points and derive the work done from the potential difference. Some participants question the method and suggest checking the calculations for potential at point B and the corresponding work done.

Discussion Status

Participants are engaged in clarifying the approach to calculating work in electron-volts versus Joules. There is a focus on ensuring the correct interpretation of the charge of the electron and its impact on the final answer. Guidance has been offered regarding the symbolic representation of constants in the calculations.

Contextual Notes

There is an emphasis on the need to express energy in electron-volts for comparison with provided answer choices. Participants are also addressing the implications of using the negative charge of the electron in their calculations.

victorializ
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Homework Statement



Screen Shot 2014-06-06 at 5.05.49 PM.png


Point charges, Q1 = +56 nC and Q2 = -98 nC, are placed as shown. In Figure 18.1a, an external force transports an electron from point A to point B. The work done by the external force is closest to:
A) +620 eV
B) -920 eV
C) -620 eV
D) +920 eV
E) +770 eV

Homework Equations



v= kq/r
W= e (Vb-Va)

The Attempt at a Solution



i know I'm doing this completely wrong. i tried to get the electric potential at A from charge 1 & 2 and then added them. i did the same for the electric potential at point b from charge 1 & 2 . once i had the summed potentials i found the difference and then multiplied by the charge of an electron .

for A[(9 x 10^9) x (56 x 10^-9)/.6] + [(9x 10^ 9) x (-98 x 10^-9)/1 ] = -42 V

for B : [(9 x 10^9) x (56 x 10^-9)/1] + [(9x 10^ 9) x (-98 x 10^-9)/.6] =-966

Vb-Va = -924 V
-924 x (1.6 x 10 ^-19 ) = -1.47 x 10 ^ -16 eV which is nowhere close. i must be approaching this the wrong way.
 
Last edited:
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Your method seems fine. What do you get for the potential at B and for the work done?
 
haruspex said:
Your method seems fine. What do you get for the potential at B and for the work done?

i just edited and added the rest of my calculations in the original thread post! i must be doing something wrong .
the answer is supposed to be D) +920 eV
 
Your calculated energy is measured in Joules. You want it measure in eV's so that you can compare it with the possible choices. Hint: do not plug in the value of the constant e. Leave it symbolically as e.

EDIT: also keep in mind that the charge of the electron is -e, not e.
 
dauto said:
Your calculated energy is measured in Joules. You want it measure in eV's so that you can compare it with the possible choices. Hint: do not plug in the value of the constant e. Leave it symbolically as e.

EDIT: also keep in mind that the charge of the electron is -e, not e.

so rather than multiplying it i would just leave my answer in joules but basically multiply by -1 because of -e which would leave me with about +920eV?
 
Last edited:
victorializ said:
so rather than multiplying it i would just leave my answer in joules but basically multiply by -1 because of -e which would leave me with about +920eV?

Yes except that you're not leaving your answer in Joules. You're leaving it in eVs. I assume that was a typo.
 
dauto said:
Yes except that you're not leaving your answer in Joules. You're leaving it in eVs. I assume that was a typo.

yes it was sorry haha. that makes sense thank you!

so why exactly don't you multiply it by the e constant?
 
victorializ said:
yes it was sorry haha. that makes sense thank you!

so why exactly don't you multiply it by the e constant?

You do multiply by the e constant symbolically at the unit. The unit of volts "V" times the constant "e" equal the unit electron-volts. Symbolically you have
e * Volt = electron-volt or
e V = eV.
 
dauto said:
You do multiply by the e constant symbolically at the unit. The unit of volts "V" times the constant "e" equal the unit electron-volts. Symbolically you have
e * Volt = electron-volt or
e V = eV.

oh wow okay that makes so much more sense ! thank you so much for all your help!
 

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