Work Done by Braking Force to Stop a 1240 kg Car at 86.0 km/hr

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SUMMARY

The discussion focuses on calculating the work done by the braking force to stop a 1240 kg car traveling at 86.0 km/hr. Utilizing the Work-Energy theorem, the work done is equivalent to the change in kinetic energy of the car. The kinetic energy can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass and v is the velocity. Participants emphasize the importance of showing calculations to identify errors in the problem-solving process.

PREREQUISITES
  • Understanding of the Work-Energy theorem
  • Knowledge of kinetic energy calculations
  • Familiarity with basic physics concepts such as mass and velocity
  • Ability to perform unit conversions (e.g., km/hr to m/s)
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  • Research the Work-Energy theorem in detail
  • Learn how to convert units from km/hr to m/s for physics problems
  • Practice calculating kinetic energy for different masses and velocities
  • Explore examples of work done in various physics scenarios
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of work and energy in mechanics.

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With brakes fully applied, a 1240 kg car deccelerates from a speed of 86.0 km/hr. What is the work done by the braking force in bringing the car to a stop?

What is the change in the kinetic energy of the car?


I keep trying and it saying my answers are wrong can anyone help?
 
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You need to show your work so we can see what mistake you're making.
 
(Name deleted by mod) said:
Moderator's note: answer deleted by Redbelly98.

It's possible to solve the question using the Work-Energy theorem. You've pretty much solved it in your post without noticing.

You aren't asked for the force or the distance, just the work done in bringing the car to a halt, and that's straightforward.
 
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