Work Done by Force from 0 to 2 m - 20.4J

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Homework Help Overview

The discussion revolves around calculating the work done by a force over a distance from x = 0 to x = 2 m, using a graph where force is represented on the y-axis and distance on the x-axis. The original poster is attempting to determine the work based on the area under the curve, specifically counting boxes on the graph.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss counting boxes under the curve to estimate work done, questioning whether each box corresponds to 1 Joule. There is exploration of the relationship between the dimensions of the boxes and the units of work.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on how to interpret the graph and calculate work based on the dimensions of the boxes. There is a focus on understanding the scale of the graph and how it relates to the calculation of work.

Contextual Notes

There are discussions about the increments on the axes of the graph, specifically noting the scales for both the x-axis and y-axis, which may affect the interpretation of the area under the curve.

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Homework Statement


337713766.jpg


a) What is the work done by the force from x = 0 to x = 2 m?


Homework Equations


Work = Integral of Force Dx


The Attempt at a Solution


I was told since the equation for Force is not given, my best bet is to count the boxes under the curve from x=0 to x=2. I counted a total approx. of 20.4 boxes = 20.4J am I doing something wrong?
Thanks for helping.
 
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maniacp08 said:

Homework Statement


337713766.jpg


a) What is the work done by the force from x = 0 to x = 2 m?


Homework Equations


Work = Integral of Force Dx


The Attempt at a Solution


I was told since the equation for Force is not given, my best bet is to count the boxes under the curve from x=0 to x=2. I counted a total approx. of 20.4 boxes = 20.4J am I doing something wrong?
Thanks for helping.
Is each box equivalent 1J?
 
Y axis is measured in Newtons
X axis is measured in meters

isn't 1 full box, is a Newton*Meters = 1 J?
 
maniacp08 said:
Y axis is measured in Newtons
X axis is measured in meters

isn't 1 full box, is a Newton*Meters = 1 J?
Look at the scale on the graph.

How many increments per meter? How many increments per Newton?
 
Oh, is .25m increment for x-axis and .5Newton increment for y axis.

If I counted to be approx. 20.4 boxes
How would I calculate the work?

Or I should do each box?
say first .25m is .5n * .25m and
.50m is .50m * 1n?
 
First work out how much each box is worth (i.e. 0.25*0.5 Joules) and then multiply this by the total number of boxes.
 
Thanks Hootenanny!
Time to start cracking on those graph problems.
 
maniacp08 said:
Thanks Hootenanny!
Time to start cracking on those graph problems.
No problem :smile:
 

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